如何使用 C# 上传文件?我需要从 dialogWindow 上传文件。
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5 回答
63
using Microsoft.WindowsAzure.Storage;
using Microsoft.WindowsAzure.Storage.Auth;
using Microsoft.WindowsAzure.Storage.Blob;
// Retrieve storage account from connection string.
CloudStorageAccount storageAccount = CloudStorageAccount.Parse("StorageKey");
// Create the blob client.
CloudBlobClient blobClient = storageAccount.CreateCloudBlobClient();
// Retrieve reference to a previously created container.
CloudBlobContainer container = blobClient.GetContainerReference("mycontainer");
// Retrieve reference to a blob named "myblob".
CloudBlockBlob blockBlob = container.GetBlockBlobReference("myblob");
// Create or overwrite the "myblob" blob with contents from a local file.
using (var fileStream = System.IO.File.OpenRead(@"path\myfile"))
{
blockBlob.UploadFromStream(fileStream);
}
请参阅此处了解所需的 SDK 和参考资料
我认为这是你需要的
于 2013-09-03T17:17:13.073 回答
5
Since WindowsAzure.Storage is legacy. With Microsoft.Azure.Storage.* we can use the following code to upload
static async Task CreateBlob()
{
BlobServiceClient blobServiceClient = new BlobServiceClient(storageconnstring);
BlobContainerClient containerClient = blobServiceClient.GetBlobContainerClient(containerName);
BlobClient blobClient = containerClient.GetBlobClient(filename);
using FileStream uploadFileStream = File.OpenRead(filepath);
await blobClient.UploadAsync(uploadFileStream, true);
uploadFileStream.Close();
}
于 2020-12-22T12:15:27.357 回答
3
以下代码片段是执行文件上传的最简单形式。我在此代码中添加了几行,以检测上传文件类型并检查容器是否存在。
注意:- 您需要先添加以下 NuGet 包。
Microsoft.AspNetCore.StaticFiles
Microsoft.Azure.Storage.Blob
Microsoft.Extensions.Configuration
static void Main(string[] args) { Console.WriteLine("Hello World!"); string connstring = "DefaultEndpointsProtocol=https;AccountName=storageaccountnewne9d7b;AccountKey=3sUU8J5pQQ+6YYIi+b5jo+BiSb5XPt027Rve6N5QP9iPEhMXZAbzUfsuW7QDWi1gSPecsPFpC6AzmA9jwPYs6g==;EndpointSuffix=core.windows.net"; string containername = "newturorial"; string finlename = "TestUpload.docx"; var fileBytes = System.IO.File.ReadAllBytes(@"C:\Users\Namal Wijekoon\Desktop\HardningSprint2LoadTest\" + finlename); var cloudstorageAccount = CloudStorageAccount.Parse(connstring); var cloudblobClient = cloudstorageAccount.CreateCloudBlobClient(); var containerObject = cloudblobClient.GetContainerReference(containername); //check the container existance if (containerObject.CreateIfNotExistsAsync().Result) { containerObject.SetPermissionsAsync(new BlobContainerPermissions { PublicAccess = BlobContainerPublicAccessType.Blob }); } var fileobject = containerObject.GetBlockBlobReference(finlename); //check the file type string file_type; var provider = new FileExtensionContentTypeProvider(); if(!provider.TryGetContentType(finlename, out file_type)) { file_type = "application/octet-stream"; } fileobject.Properties.ContentType = file_type; fileobject.UploadFromByteArrayAsync(fileBytes, 0 , fileBytes.Length); string fileuploadURI = fileobject.Uri.AbsoluteUri; Console.WriteLine("File has be uploaded successfully."); Console.WriteLine("The URL of the Uploaded file is : - \n" + fileuploadURI); }
于 2021-01-03T17:32:45.060 回答
2
我们可以使用BackgroundUploader类,然后我们需要提供StorageFile对象和一个Uri:必需的命名空间:
using System;
using System.Collections.Generic;
using System.Threading;
using System.Threading.Tasks;
using Windows.Foundation;
using Windows.Foundation.Collections;
using Windows.Networking.BackgroundTransfer;
using Windows.Storage.Pickers;
using Windows.Storage;
过程如下: Uri 使用通过 UI 输入字段提供的字符串值定义,当最终用户通过提供的 UI 选择文件时,返回由 StorageFile 对象表示的所需上传文件PickSingleFileAsync 操作
Uri uri = new Uri(serverAddressField.Text.Trim());
FileOpenPicker picker = new FileOpenPicker();
picker.FileTypeFilter.Add("*");
StorageFile file = await picker.PickSingleFileAsync();
接着:
BackgroundUploader uploader = new BackgroundUploader();
uploader.SetRequestHeader("Filename", file.Name);
UploadOperation upload = uploader.CreateUpload(uri, file);
// Attach progress and completion handlers.
await HandleUploadAsync(upload, true);
就这样
于 2013-09-03T16:55:13.813 回答
1
这是完整的方法。
[HttpPost]
public ActionResult Index(Doctor doct, HttpPostedFileBase photo)
{
try
{
if (photo != null && photo.ContentLength > 0)
{
// extract only the fielname
var fileName = Path.GetFileName(photo.FileName);
doct.Image = fileName.ToString();
CloudStorageAccount cloudStorageAccount = DoctorController.GetConnectionString();
CloudBlobClient cloudBlobClient = cloudStorageAccount.CreateCloudBlobClient();
CloudBlobContainer cloudBlobContainer = cloudBlobClient.GetContainerReference("images");
string imageName = Guid.NewGuid().ToString() + "-" +Path.GetExtension(photo.FileName);
CloudBlockBlob BlockBlob = cloudBlobContainer.GetBlockBlobReference(imageName);
BlockBlob.Properties.ContentType = photo.ContentType;
BlockBlob.UploadFromStreamAsync(photo.InputStream);
string imageFullPath = BlockBlob.Uri.ToString();
var memoryStream = new MemoryStream();
photo.InputStream.CopyTo(memoryStream);
memoryStream.ToArray();
memoryStream.Seek(0, SeekOrigin.Begin);
using (var fs = photo.InputStream)
{
BlockBlob.UploadFromStreamAsync(memoryStream);
}
}
}
catch (Exception ex)
{
}
return View();
}
getconnectionstring 方法在哪里。
static string accountname = ConfigurationManager.AppSettings["accountName"];
static string key = ConfigurationManager.AppSettings["key"];
public static CloudStorageAccount GetConnectionString()
{
string connectionString = string.Format("DefaultEndpointsProtocol=https;AccountName={0};AccountKey={1}", accountname, key);
return CloudStorageAccount.Parse(connectionString);
}
于 2017-12-29T21:14:17.547 回答