我正在使用这个 re.match 调用来获取“正确”的字符串：
re.match('^[A-Za-z0-9\.\,\:\;\!\?\(\)]', str)
但我也得到了一些垃圾，比如#and _。这怎么可能？我究竟做错了什么？
谢谢！
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Use this to check all characters until the end of your string, otherwhise your pattern will only check the first character:
re.match('^[A-Za-z0-9.,:;!?()]+$', str)
Note that the character class doesn't contain spaces, newlines or tabs. You can add them like this:
re.match('^[A-Za-z0-9.,:;!?()\s]+$', str)
If you want to allow void strings you can replace the + quantifier by *
于 2013-09-03T14:21:19.753 回答