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我正在尝试使用以下电子邮件向多个收件人发送电子邮件，但它只发送到第一封电子邮件，知道为什么以及如何发送给多个收件人吗？

from email.mime.text import MIMEText
from smtplib import SMTP

def email (body,subject,SendToList):
    msg = MIMEText("%s" % body, 'html')
    msg['Content-Type'] = "text/html; charset=UTF8"
    msg['Subject'] = subject
    s = SMTP('localhost',25)
    s.sendmail('fromuserid@company.com', SendToList,msg=msg.as_string())

def main ():
    SendToList = 'userid1@company.com,userid2@company.com'
    with open('email.txt', 'r') as f:
        body = f.read()
    subject = "test email"
    email(body,subject,SendToList)
    print "Done"

if __name__ == '__main__':
    main()
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1 回答 1

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从文档中：

SMTP.sendmail(from_addr, to_addrs, msg[, mail_options, rcpt_options])

发邮件。所需的参数是 RFC 822 发件人地址字符串、 RFC 822 收件人地址字符串列表（裸字符串将被视为具有 1 个地址的列表）和消息字符串。

所以你需要给它发送一个列表：

def main ():
    send_to_list = ['userid1@company.com','userid2@company.com']
于 2013-09-03T06:33:30.683 回答