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我有一个获得 PayPal 身份验证的请求。它是用 Curl 编写的，并且运行良好。尝试用 Python 重写它会导致错误响应（500000 内部错误）。谁能指导我如何重写或纠正我现有的代码。

卷曲

curl -s --insecure -H "X-PAYPAL-SECURITY-USERID: <user_id>" -H "X-PAYPAL-SECURITY-PASSWORD: <user_password>" -H "X-PAYPAL-SECURITY-SIGNATURE: <user_signature>" -H "X-PAYPAL-REQUEST-DATA-FORMAT: JSON" -H "X-PAYPAL-RESPONSE-DATA-FORMAT: JSON" -H "X-PAYPAL-APPLICATION-ID: APP-80W284485P519543T" https://svcs.sandbox.paypal.com/Permissions/RequestPermissions -d "{\"scope\":\"EXPRESS_CHECKOUT\", \"callback\":\"<callback_url>",  \"requestEnvelope\": {\"errorLanguage\":\"en_US\"}}"

PYTHON

import settings
import urllib
import urllib2
from django.utils import simplejson

def home(request):
    headers = {
    "X-PAYPAL-SECURITY-USERID": settings.USERNAME,
    "X-PAYPAL-SECURITY-PASSWORD": settings.PASSWORD,
    "X-PAYPAL-SECURITY-SIGNATURE": settings.SIGNATURE,
    "X-PAYPAL-REQUEST-DATA-FORMAT": "JSON",
    "X-PAYPAL-RESPONSE-DATA-FORMAT": "JSON",
    "X-PAYPAL-APPLICATION-ID": "APP-80W284485P519543T"
    }

    data = {"scope":"EXPRESS_CKECKOUT", callback":"http://www.example.com/success.html", "requestEnvelope": {"errorLanguage":"en_US"}}
    req = urllib2.Request("https://svcs.sandbox.paypal.com/Permissions/RequestPermissions/", simplejson.dumps(data), urllib.urlencode(data), headers)    
    res = urllib2.urlopen(req).read()
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1 回答 1

3

拼写错误，"EXPRESS_CKECKOUT"而不是"EXPRESS_CHECKOUT"第三个参数urllib.urlencode(data)forurllib2.Request不是必需的。

data = {"scope":"EXPRESS_CHECKOUT", "callback":"http://www.example.com/success.html", "requestEnvelope": {"errorLanguage":"en_US"}}
req = urllib2.Request("https://svcs.sandbox.paypal.com/Permissions/RequestPermissions/", simplejson.dumps(data), headers)
res = urllib2.urlopen(req).read()
于 2013-09-03T04:50:53.253 回答