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我一直在尝试从多个 tag_ids 到 pub_ids 的单个表上的此查询修改中获得预期结果

SELECT t1.pub_id
FROM `wp_teachpress_relation` AS t1
LEFT JOIN `wp_teachpress_relation` AS t2 ON t2.pub_id =356
AND t1.pub_id =1
WHERE t1.pub_id != t2.pub_id

356 是“美国”的标签 ID，1 是“大学”的标签 ID

我想要所有拥有 tag_id(1) 大学但没有 tag_id(356) 美国的 pub_id ......我想我缺少的是这个查询在同一张表上运行的事实？

数据示例和预期结果：

-- phpMyAdmin SQL Dump
-- version 2.11.11.3
-- http://www.phpmyadmin.net
--
-- Host: 68.178.140.228
-- Generation Time: Sep 02, 2013 at 11:08 AM
-- Server version: 5.0.96
-- PHP Version: 5.1.6

SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";

--
-- Database: `eco1308903180169`
--

-- --------------------------------------------------------

--
-- Table structure for table `wp_teachpress_relation`
--

CREATE TABLE `wp_teachpress_relation` (
  `con_id` int(10) unsigned NOT NULL auto_increment,
  `pub_id` int(10) unsigned default NULL,
  `tag_id` int(10) unsigned default NULL,
  PRIMARY KEY  (`con_id`),
  KEY `pub_id` (`pub_id`),
  KEY `tag_id` (`tag_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=25618 ;

--
-- Dumping data for table `wp_teachpress_relation`
--

INSERT INTO `wp_teachpress_relation` VALUES(10, 10285, 1);
INSERT INTO `wp_teachpress_relation` VALUES(20, 10285, 306);
INSERT INTO `wp_teachpress_relation` VALUES(30, 10286, 1);
INSERT INTO `wp_teachpress_relation` VALUES(40, 10286, 306);
INSERT INTO `wp_teachpress_relation` VALUES(50, 10287, 1);
INSERT INTO `wp_teachpress_relation` VALUES(60, 10287, 356);
INSERT INTO `wp_teachpress_relation` VALUES(62, 10287, 299);
INSERT INTO `wp_teachpress_relation` VALUES(70, 10288, 1);
INSERT INTO `wp_teachpress_relation` VALUES(80, 10288, 356);
INSERT INTO `wp_teachpress_relation` VALUES(90, 10288, 299);

好的，所以在小提琴上运行您的查询给了我正确的结果......也许问题来自完整查询中的其他连接？

 SELECT r.tag_id tag_id, t.name name, count( r.tag_id ) tagPeak
FROM (

SELECT t1.pub_id
FROM wp_teachpress_relation AS t1
LEFT JOIN wp_teachpress_relation AS t2 ON t1.pub_id = t2.pub_id
AND t2.tag_id =356
WHERE t1.tag_id =1
AND t2.pub_id IS NULL
)pubs
JOIN `wp_teachpress_relation` r ON pubs.pub_id = r.pub_id
JOIN `wp_teachpress_tags` t ON t.tag_id = r.tag_id
WHERE r.tag_id <>1
AND t.name LIKE 'v%'
GROUP BY tag_id
ORDER BY name ASC
LIMIT 0 , 30

附加表出版物

-- phpMyAdmin SQL Dump
-- version 2.11.11.3
-- http://www.phpmyadmin.net
--
-- Host: 68.178.140.228
-- Generation Time: Sep 02, 2013 at 12:51 PM
-- Server version: 5.0.96
-- PHP Version: 5.1.6

SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";

--
-- Database: `eco1308903180169`
--

-- --------------------------------------------------------

--
-- Table structure for table `wp_teachpress_pub`
--

CREATE TABLE `wp_teachpress_pub` (
  `pub_id` int(10) unsigned NOT NULL auto_increment,
  `title` varchar(500) default NULL,
  `type` varchar(50) default NULL,
  `bibtex` varchar(50) default NULL,
  `author` varchar(500) default NULL,
  `editor` varchar(500) default NULL,
  `isbn` varchar(50) default NULL,
  `url` text,
  `date` date default NULL,
  `urldate` date default NULL,
  `booktitle` varchar(200) default NULL,
  `issuetitle` varchar(200) default NULL,
  `journal` varchar(200) default NULL,
  `volume` varchar(40) default NULL,
  `number` varchar(40) default NULL,
  `pages` varchar(40) default NULL,
  `publisher` varchar(500) default NULL,
  `address` varchar(300) default NULL,
  `edition` varchar(100) default NULL,
  `chapter` varchar(40) default NULL,
  `institution` varchar(200) default NULL,
  `organization` varchar(200) default NULL,
  `school` varchar(200) default NULL,
  `series` varchar(200) default NULL,
  `crossref` varchar(100) default NULL,
  `abstract` text,
  `howpublished` varchar(200) default NULL,
  `key` varchar(100) default NULL,
  `techtype` varchar(200) default NULL,
  `comment` text,
  `note` text,
  `image_url` varchar(400) default NULL,
  `rel_page` int(11) default NULL,
  `is_isbn` int(1) default NULL,
  PRIMARY KEY  (`pub_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=11764 ;

--
-- Dumping data for table `wp_teachpress_pub`
--

INSERT INTO `wp_teachpress_pub` VALUES(10285, 'Universidad del Centro Educativo Latinoamericano Rosario', 'misc', 'sc-2014-31', '', '', '', 'http://www.ucel.edu.ar/', '2012-06-22', '0000-00-00', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', 0, 1);
INSERT INTO `wp_teachpress_pub` VALUES(10286, 'Universidad del Cine - Buenos Aires', 'misc', 'sc-2014-32', '', '', '', 'http://www.ucine.edu.ar/', '2012-06-22', '0000-00-00', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', 0, 1);
INSERT INTO `wp_teachpress_pub` VALUES(10287, 'Instituto Universitario Aeronáutico', 'misc', 'sc-2014-33', '', '', '', 'http://www.iua.edu.ar/', '2012-06-22', '0000-00-00', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', 0, 1);
INSERT INTO `wp_teachpress_pub` VALUES(10288, 'Universidad del Museo Social Argentino', 'misc', 'sc-2014-34', '', '', '', 'http://www.umsa.edu.ar/', '2012-06-22', '0000-00-00', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', '', 0, 1);

附加标签表

-- phpMyAdmin SQL Dump
-- version 2.11.11.3
-- http://www.phpmyadmin.net
--
-- Host: 68.178.140.228
-- Generation Time: Sep 02, 2013 at 01:02 PM
-- Server version: 5.0.96
-- PHP Version: 5.1.6

SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";

--
-- Database: `eco1308903180169`
--

-- --------------------------------------------------------

--
-- Table structure for table `wp_teachpress_tags`
--

CREATE TABLE `wp_teachpress_tags` (
  `tag_id` int(10) unsigned NOT NULL auto_increment,
  `name` varchar(300) default NULL,
  PRIMARY KEY  (`tag_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=357 ;

--
-- Dumping data for table `wp_teachpress_tags`
--

INSERT INTO `wp_teachpress_tags` VALUES(306, 'Chile');
INSERT INTO `wp_teachpress_tags` VALUES(64, 'China');
INSERT INTO `wp_teachpress_tags` VALUES(365, 'United states');
INSERT INTO `wp_teachpress_tags` VALUES(1, 'university');
INSERT INTO `wp_teachpress_tags` VALUES(299, 'california');
4

2 回答 2

0

这是一个标准的 LEFT JOIN 习语，你应该学习它：

SELECT t1.pub_id 
FROM wp_teachpress_relation AS t1 
LEFT JOIN wp_teachpress_relation AS t2 ON t1.pub_id = t2.pub_id and t2.tag_id = 356
WHERE t1.tag_id = 1
and t2.pub_id IS NULL
于 2013-09-02T13:37:18.757 回答
0 
SELECT t1.pub_id 
FROM wp_teachpress_relation AS t1 
LEFT JOIN wp_teachpress_relation AS t2 ON t1.pub_id = t2.pub_id 
WHERE t1.pub_id = 1
group by t1.pub_id 
HAVING count(t2.pub_id = 356) = 0
于 2013-09-02T13:31:06.460 回答