1

当我的 WEBSERVICE 没有返回数据时，我想添加一条 toast 消息并将用户返回到主要活动，并允许我解释更多。当用户搜索查询时，Web 服务将数据返回到我的 JSON 字符串，如下所示。

08-30 00:36:07.917: D/JSON String(1891): {
08-30 00:36:07.917: D/JSON String(1891): "all" :    {
08-30 00:36:07.917: D/JSON String(1891):    "count" : 25,
08-30 00:36:07.917: D/JSON String(1891):    "questions" : [     {   
08-30 00:36:07.917: D/JSON String(1891):            "Id" : "20100728112033AAb4hTA",
08-30 00:36:07.917: D/JSON String(1891):            "Subject" : "What is the oldest a bitch can more or less safely breed?",
08-30 00:36:07.917: D/JSON String(1891):            "Content" : "Don't worry I'm not going to breed - both my bitches are getting neutered in the next year, as is my dog! Just that me and a friend were talking about it after talking to the man who gave me Misty (my border collie) who said she could still breed at 7 - I thought the oldest was 5?\n",
08-30 00:36:07.917: D/JSON String(1891):            "Date" : "2010-07-28 18:20:33",
08-30 00:36:07.917: D/JSON String(1891):            "Timestamp" : "1280341233",
08-30 00:36:07.917: D/JSON String(1891):            "Link" : "http://answers.yahoo.com/question/?qid=20100728112033AAb4hTA",
08-30 00:36:07.917: D/JSON String(1891):            "Type" : "Answered",
08-30 00:36:07.917: D/JSON String(1891):            "CategoryId" : 396546021,
08-30 00:36:07.917: D/JSON String(1891):            "CategoryName" : "Dogs",
08-30 00:36:07.917: D/JSON String(1891):            "UserId" : "cP16Ctgxaa",
08-30 00:36:07.917: D/JSON String(1891):            "UserNick" : "Kiko",
08-30 00:36:07.917: D/JSON String(1891):            "UserPhotoURL" : "http://l.yimg.com/dg/users/1t1USxJpxAAEBQOGZjBMW0-5Wp_EG.medium.jpg",
08-30 00:36:07.917: D/JSON String(1891):            "NumAnswers" : 8,
08-30 00:36:07.917: D/JSON String(1891):            "NumComments" : 0,
08-30 00:36:07.917: D/JSON String(1891):            "ChosenAnswer" : "You just \"imagined\" that ,dear...not \"thought\". & your imagination is WRONG.\r\n\r\n9 or even 10,for a healthy TOP-PRODUCING bitc-h.\r\n\r\n\r\n\r\n*&* bitches are SPAYED & dogs are CASTRATED......big scary correct ADULT words.",
08-30 00:36:07.917: D/JSON String(1891):            "ChosenAnswererId" : "clN6YITvaa",
08-30 00:36:07.917: D/JSON String(1891):            "ChosenAnswererNick" : "Debunker",
08-30 00:36:07.917: D/JSON String(1891):            "ChosenAnswerTimestamp" : "1280317077",
08-30 00:36:07.917: D/JSON String(1891):            "ChosenAnswerAwardTimestamp" : "1280835336"
08-30 00:36:07.917: D/JSON String(1891):        },      {

这是我如何解析这些数据以获取我想要的特定数据的代码

protected String doInBackground(String... args) {

    try {
        Intent in = getIntent();
        String searchTerm = in.getStringExtra("TAG_SEARCH");
        String query = URLEncoder.encode(searchTerm, "utf-8");
        String URL = "http://example.com";
        JSONParsser jParser = new JSONParsser();
        JSONObject json = jParser.readJSONFeed(URL);
        try {

            JSONArray questions = json.getJSONObject("all").getJSONArray("questions");

            for(int i = 0; i < questions.length(); i++) {
                JSONObject question = questions.getJSONObject(i);


            String Subject = question.getString(TAG_QUESTION_SUBJECT);
            String ChosenAnswer = question.getString(TAG_QUESTION_CHOSENANSWER);
            String Content = question.getString(TAG_QUESTION_CONTENT);


            }


        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    } catch (UnsupportedEncodingException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

        return TAG_QUESTION ;           

}

但是，当用户搜索查询并且 Web 服务没有返回任何结果并且没有结果时，我的意思是 Web 服务数据具有"count" : 0,并且在我的 JSON 字符串中看起来像这样。

09-02 00:25:55.466: D/JSON String(882): {
09-02 00:25:55.466: D/JSON String(882): "all" : {
09-02 00:25:55.466: D/JSON String(882):     "count" : 0,
09-02 00:25:55.466: D/JSON String(882):     "questions" : [     ]
09-02 00:25:55.466: D/JSON String(882):     }
09-02 00:25:55.466: D/JSON String(882): }

发生这种情况时，我希望弹出一条 toast 消息并将用户返回到主要活动，但我只是不知道当它返回计数 0 时如何解析该数据。我已经知道我需要if在此位置添加一条语句

        try {
            // if statement here
            JSONArray questions = json.getJSONObject("all").getJSONArray("questions");

            for(int i = 0; i < questions.length(); i++) {
                JSONObject question = questions.getJSONObject(i);


            String Subject = question.getString(TAG_QUESTION_SUBJECT);
            String ChosenAnswer = question.getString(TAG_QUESTION_CHOSENANSWER);
            String Content = question.getString(TAG_QUESTION_CONTENT);

我需要知道如何解析"count" : 0,，以便显示 toast 消息，然后将用户返回到主要活动。希望你在这里看到我的想法，如果你有任何困难，请告诉我，试着理解我的意思。PS如果你想知道JSONParsser是什么，它只是我用来连接到网络服务的类，searchTerm我只是传递editText和编码它。

@Override
protected void onPostExecute(String file_URL) { 

    if(file_URL.equals("0")) { 
        pDialog.dismiss();
        Toast.makeText(ListView.this, "No data found", Toast.LENGTH_SHORT).show();
        finish();    

}else{

        if (pDialog.isShowing()) pDialog.dismiss();
        ListAdapter adapter = new SimpleAdapter(getBaseContext(), questionList,
                R.layout.listelements,
                new String[] { TAG_QUESTION_SUBJECT }, new int[] {
                R.id.Subject,});

        setListAdapter(adapter);
}

更新 

        protected JSONObject doInBackground(String... args) {  

            JSONObject json = new JSONObject();
            try {
                Intent in = getIntent();
                String searchTerm = in.getStringExtra("TAG_SEARCH");
                String query = URLEncoder.encode(searchTerm, "utf-8");
                String URL = "http://example.com";
                JSONParsser jParser = new JSONParsser();

                    json = jParser.readJSONFeed(URL);
                } catch (UnsupportedEncodingException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }

                return json;           

            }

        @Override
        protected void onPostExecute(JSONObject json) { 

            int count = 0;
            try {
                count = json.getJSONObject("all").getInt("count");
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            if(count>0) { 
                pDialog.dismiss();
                Toast.makeText(ListView.this, "No data found", Toast.LENGTH_SHORT).show();
                finish();    

        }else{

                try {

                    JSONArray questions = json.getJSONObject("all").getJSONArray("questions");

                    for(int i = 0; i < questions.length(); i++) {
                        JSONObject question = questions.getJSONObject(i);


                    String Subject = question.getString(TAG_QUESTION_SUBJECT);
                    String ChosenAnswer = question.getString(TAG_QUESTION_CHOSENANSWER);
                    String Content = question.getString(TAG_QUESTION_CONTENT);

                    HashMap<String, String> map = new HashMap<String, String>();

                    map.put(TAG_QUESTION_SUBJECT, Subject);
                    map.put(TAG_QUESTION_CONTENT, Content);
                    map.put(TAG_QUESTION_CHOSENANSWER, ChosenAnswer);

                    questionList.add(map);

                    pDialog.dismiss();
                    ListAdapter adapter = new SimpleAdapter(getBaseContext(), questionList,
                                R.layout.listelements,
                                new String[] { TAG_QUESTION_SUBJECT }, new int[] {
                                R.id.Subject,});

                        setListAdapter(adapter);
                    }

                } catch (JSONException e) {
                    // TODO Auto-generated catch block
                    e.printStackTrace();
                }

        }


    }

}
4

3 回答 3

2

要获得count价值，只需执行

int count = json.getJSONObject("all").getInt("count");

（您应该像在代码"count"中使用另一个变量一样替换为最终变量）JSONObject

if然后在你做之前添加一个

JSONArray questions = json.getJSONObject("all").getJSONArray("questions");

但是您将无法在doInBackground方法中显示您的 toast，您必须返回结果（一个字符串）并将其显示在onPostExecute(). 到目前为止，您没有返回正确的值，而是 return TAG_QUESTION，它必须是最终的 String，这意味着您的处理结果永远不会在方法之外使用。

更新

我认为你应该这样做：

首先，您不应该在doInBackground(). 在这种方法中，您应该只检索您的 json，将其返回并在onPostExecute(). 为此，您需要更改您的AsyncTask，使其看起来像这样（注意最后一个参数的变化，从Stringto JSONObject）：

private class yourAsyncTask extends AsyncTask<String, Void, JSONObject> {

这将告诉您的程序返回值doInBackground()将是JSONObject类型。所以你接下来要做的是改变你的doInBackground()，让它看起来像这样（再次注意返回值的变化，从Stringto JSONObject：

protected JSONObject doInBackground(String... args) {
    JSONObject json = new JSONObject();
    try {
        Intent in = getIntent();
        String searchTerm = in.getStringExtra("TAG_SEARCH");
        String query = URLEncoder.encode(searchTerm, "utf-8");
        String URL = "http://example.com";
        JSONParsser jParser = new JSONParsser();

        try {
            json = jParser.readJSONFeed(URL);
        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    } catch (UnsupportedEncodingException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

    return json;           

}

然后把里面的参数的类型改成 ，onPostExecute()检查值JSONObject后进行处理：count

@Override
protected void onPostExecute(JSONObject json) { 

    int count = json.getJSONObject("all").getInt("count");
    if(count>0) {   // There are some questions to retrieve

        /*  In this part I just copied what you put in your question, 
            I don't know what your goal is so I can't help much, 
            but you have the logic to do so */

        JSONArray questions = json.getJSONObject("all").getJSONArray("questions");

        for(int i = 0; i < questions.length(); i++) {
            JSONObject question = questions.getJSONObject(i);


        String Subject = question.getString(TAG_QUESTION_SUBJECT);
        String ChosenAnswer = question.getString(TAG_QUESTION_CHOSENANSWER);
        String Content = question.getString(TAG_QUESTION_CONTENT);

        if (pDialog.isShowing()) pDialog.dismiss();
        ListAdapter adapter = new SimpleAdapter(getBaseContext(), questionList,
            R.layout.listelements,
            new String[] { TAG_QUESTION_SUBJECT }, new int[] {
            R.id.Subject,});

        setListAdapter(adapter);

    } else {

        Toast.makeText(ListView.this, "No data found", Toast.LENGTH_SHORT).show();
        finish();    

    }

}
于 2013-09-02T00:57:04.853 回答
1

这样你可以检查对象是否可用（假设在没有问题的情况下count返回0）

import com.google.gson.JsonObject;
import com.google.gson.JsonParser;

public class Test {
    static String str = "{" + 
        "\"all\" : {" + 
        "    \"count\" : 0," + 
        "    \"questions\" : [     ]" + 
        "    }" + 
        "}";

public static void main(String[] args) {
    // TODO Auto-generated method stub
    try {

                  JsonParser jsonParser = new JsonParser();
                  JsonObject jsonString = (JsonObject)jsonParser.parse(str);
                  JsonObject allObj = jsonString.getAsJsonObject("all");

                  int quesCount = allObj.get("count").getAsInt();
                  if(quesCount == 0){
                  System.out.println("No Object Available as Object Count is : "+quesCount);
                }
      } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

}
于 2013-09-02T10:17:51.693 回答
0

这样做

protected String doInBackground(String... args) {

    try {
        Intent in = getIntent();
        String searchTerm = in.getStringExtra("TAG_SEARCH");
        String query = URLEncoder.encode(searchTerm, "utf-8");
        String URL = "http://example.com";
        JSONParsser jParser = new JSONParsser();
        JSONObject json = jParser.readJSONFeed(URL);
        try {
            if(Integer.parseInt(data.getJSONObject("all").getString("count"))<=0){ //UPDATE HERE
            return "0";
        }
            JSONArray questions = json.getJSONObject("all").getJSONArray("questions");

            for(int i = 0; i < questions.length(); i++) {
                JSONObject question = questions.getJSONObject(i);


            String Subject = question.getString(TAG_QUESTION_SUBJECT);
            String ChosenAnswer = question.getString(TAG_QUESTION_CHOSENANSWER);
            String Content = question.getString(TAG_QUESTION_CONTENT);


            }


        } catch (JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
    } catch (UnsupportedEncodingException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

        return TAG_QUESTION ;           

}


@Override
            protected void onPostExecute(String result) {
                super.onPostExecute(result);
                if(result==null || result.equals("0")){
                     Toast.makeText(ActivityName.this, "No data found", Toast.LENGTH_SHORT).show();
                }

            }
于 2013-09-02T04:34:26.223 回答