有什么方法可以使用带有可编辑行的 ttk Treeview？
我的意思是它应该更像一张桌子。例如，双击该项目使#0 列“可编辑”。
如果这是不可能的，任何允许鼠标选择项目的方法都可以。我在 tkdocs 或其他文档中没有发现任何提及这一点。
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5 回答
11
经过长时间的研究，我还没有找到这样的功能，所以我想应该有。Tk 是一个非常简单的界面，它允许程序员从基础构建“高级”功能。所以我想要这样的行为。
def onDoubleClick(self, event):
''' Executed, when a row is double-clicked. Opens
read-only EntryPopup above the item's column, so it is possible
to select text '''
# close previous popups
# self.destroyPopups()
# what row and column was clicked on
rowid = self._tree.identify_row(event.y)
column = self._tree.identify_column(event.x)
# get column position info
x,y,width,height = self._tree.bbox(rowid, column)
# y-axis offset
# pady = height // 2
pady = 0
# place Entry popup properly
text = self._tree.item(rowid, 'text')
self.entryPopup = EntryPopup(self._tree, rowid, text)
self.entryPopup.place( x=0, y=y+pady, anchor=W, relwidth=1)
这是将 ttk.Treeview 组合为 self._tree 的类中的方法
然后 EntryPopup 是 Entry 的非常简单的子类：
class EntryPopup(Entry):
def __init__(self, parent, iid, text, **kw):
''' If relwidth is set, then width is ignored '''
super().__init__(parent, **kw)
self.tv = parent
self.iid = iid
self.insert(0, text)
# self['state'] = 'readonly'
# self['readonlybackground'] = 'white'
# self['selectbackground'] = '#1BA1E2'
self['exportselection'] = False
self.focus_force()
self.bind("<Return>", self.on_return)
self.bind("<Control-a>", self.select_all)
self.bind("<Escape>", lambda *ignore: self.destroy())
def on_return(self, event):
self.tv.item(self.iid, text=self.get())
self.destroy()
def select_all(self, *ignore):
''' Set selection on the whole text '''
self.selection_range(0, 'end')
# returns 'break' to interrupt default key-bindings
return 'break'
于 2013-09-15T18:17:37.890 回答
3
您还可以弹出一个工具窗口，其中包含与条目一起列出的可编辑字段以更新值。这个例子有一个三列的树视图，并且不使用子类。
将您的双击绑定到此：
def OnDoubleClick(self, treeView):
# First check if a blank space was selected
entryIndex = treeView.focus()
if '' == entryIndex: return
# Set up window
win = Toplevel()
win.title("Edit Entry")
win.attributes("-toolwindow", True)
####
# Set up the window's other attributes and geometry
####
# Grab the entry's values
for child in treeView.get_children():
if child == entryIndex:
values = treeView.item(child)["values"]
break
col1Lbl = Label(win, text = "Value 1: ")
col1Ent = Entry(win)
col1Ent.insert(0, values[0]) # Default is column 1's current value
col1Lbl.grid(row = 0, column = 0)
col1Ent.grid(row = 0, column = 1)
col2Lbl = Label(win, text = "Value 2: ")
col2Ent = Entry(win)
col2Ent.insert(0, values[1]) # Default is column 2's current value
col2Lbl.grid(row = 0, column = 2)
col2Ent.grid(row = 0, column = 3)
col3Lbl = Label(win, text = "Value 3: ")
col3Ent = Entry(win)
col3Ent.insert(0, values[2]) # Default is column 3's current value
col3Lbl.grid(row = 0, column = 4)
col3Ent.grid(row = 0, column = 5)
def UpdateThenDestroy():
if ConfirmEntry(treeView, col1Ent.get(), col2Ent.get(), col3Ent.get()):
win.destroy()
okButt = Button(win, text = "Ok")
okButt.bind("<Button-1>", lambda e: UpdateThenDestroy())
okButt.grid(row = 1, column = 4)
canButt = Button(win, text = "Cancel")
canButt.bind("<Button-1>", lambda c: win.destroy())
canButt.grid(row = 1, column = 5)
然后确认更改：
def ConfirmEntry(self, treeView, entry1, entry2, entry3):
####
# Whatever validation you need
####
# Grab the current index in the tree
currInd = treeView.index(treeView.focus())
# Remove it from the tree
DeleteCurrentEntry(treeView)
# Put it back in with the upated values
treeView.insert('', currInd, values = (entry1, entry2, entry3))
return True
以下是删除条目的方法：
def DeleteCurrentEntry(self, treeView):
curr = treeView.focus()
if '' == curr: return
treeView.delete(curr)
于 2017-02-01T22:42:13.497 回答
0
这仅用于为构造函数中设置的指定路径创建树。您可以将事件绑定到该树上的项目。事件函数以一种可以以多种方式使用该项目的方式保留。在这种情况下，双击它会显示项目的名称。希望这可以帮助某人。
import ttk
from Tkinter import*
import os*
class Tree(Frame):
def __init__(self, parent):
Frame.__init__(self, parent)
self.parent = parent
path = "/home/...."
self.initUI(path)
def initUI(self, path):
self.parent.title("Tree")
self.tree = ttk.Treeview(self.parent)
self.tree.bind("<Double-1>", self.itemEvent)
yScr = ttk.Scrollbar(self.tree, orient = "vertical", command = self.tree.yview)
xScr = ttk.Scrollbar(self.tree, orient = "horizontal", command = self.tree.xview)
self.tree.configure(yscroll = yScr.set, xScroll = xScr.set)
self.tree.heading("#0", text = "My Tree", anchor = 'w')
yScr.pack(side = RIGHT, fill = Y)
pathy = os.path.abspath(path)
rootNode = self.tree.insert('', 'end', text = pathy, open = True)
self.createTree(rootNode, pathy)
self.tree.pack(side = LEFT, fill = BOTH, expand = 1, padx = 2, pady = 2)
self.pack(fill= BOTH, expand = 1)
def createTree(self, parent, path)
for p in os.listdir(path)
pathy = os.path.join(path, p)
isdir = os.path.isdir(pathy)
oid = self.tree.insert(parent, 'end' text = p, open = False)
if isdir:
self.createTree(oid, pathy)
def itemEvent(self, event):
item = self.tree.selection()[0] # now you got the item on that tree
print "you clicked on", self.tree.item(item,"text")
def main():
root = Tk.Tk()
app = Tree(root)
root.mainloop()
if __name__ == '__main__'
main()
于 2014-07-23T11:52:51.173 回答
0
from tkinter import ttk
from tkinter import *
root = Tk()
columns = ("Items", "Values")
Treeview = ttk.Treeview(root, height=18, show="headings", columns=columns) #
Treeview.column("Items", width=200, anchor='center')
Treeview.column("Values", width=200, anchor='center')
Treeview.heading("Items", text="Items")
Treeview.heading("Values", text="Values")
Treeview.pack(side=LEFT, fill=BOTH)
name = ['Item1', 'Item2', 'Item3']
ipcode = ['10', '25', '163']
for i in range(min(len(name), len(ipcode))):
Treeview.insert('', i, values=(name[i], ipcode[i]))
def treeview_sort_column(tv, col, reverse):
l = [(tv.set(k, col), k) for k in tv.get_children('')]
l.sort(reverse=reverse)
for index, (val, k) in enumerate(l):
tv.move(k, '', index)
tv.heading(col, command=lambda: treeview_sort_column(tv, col, not reverse))
def set_cell_value(event):
for item in Treeview.selection():
item_text = Treeview.item(item, "values")
column = Treeview.identify_column(event.x)
row = Treeview.identify_row(event.y)
cn = int(str(column).replace('#', ''))
rn = int(str(row).replace('I', ''))
entryedit = Text(root, width=10 + (cn - 1) * 16, height=1)
entryedit.place(x=16 + (cn - 1) * 130, y=6 + rn * 20)
def saveedit():
Treeview.set(item, column=column, value=entryedit.get(0.0, "end"))
entryedit.destroy()
okb.destroy()
okb = ttk.Button(root, text='OK', width=4, command=saveedit)
okb.place(x=90 + (cn - 1) * 242, y=2 + rn * 20)
def newrow():
name.append('to be named')
ipcode.append('value')
Treeview.insert('', len(name) - 1, values=(name[len(name) - 1], ipcode[len(name) - 1]))
Treeview.update()
newb.place(x=120, y=(len(name) - 1) * 20 + 45)
newb.update()
Treeview.bind('<Double-1>', set_cell_value)
newb = ttk.Button(root, text='new item', width=20, command=newrow)
newb.place(x=120, y=(len(name) - 1) * 20 + 45)
for col in columns:
Treeview.heading(col, text=col, command=lambda _col=col: treeview_sort_column(Treeview, _col, False))
root.mainloop()
在做我的项目时经过这么多研究得到了这个代码，它对我帮助很大。双击您要编辑的元素，进行所需的更改，然后单击“确定”按钮我认为这正是您想要的
#python #tkinter #treeview #editablerow
于 2020-12-08T05:57:39.833 回答
-1
我不知道如何使行可编辑，但要捕获单击行，您可以使用<<TreeviewSelect>>虚拟事件。这通过该方法绑定到一个例程bind()，然后您使用该selection()方法获取所选项目的 ID。
这些是现有程序的片段，但显示了基本的调用顺序：
# in Treeview setup routine
self.tview.tree.bind("<<TreeviewSelect>>", self.TableItemClick)
# in TableItemClick()
selitems = self.tview.tree.selection()
if selitems:
selitem = selitems[0]
text = self.tview.tree.item(selitem, "text") # get value in col #0
于 2013-09-04T17:44:32.237 回答