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我正在使用以下代码从我的应用程序发送短信；

void App::sendSms(const QString &messageText, const QStringList &phoneNumbers) {
bb::pim::account::AccountService accountService;
bb::pim::message::MessageService messageService;

QList<Account> accountListy = accountService.accounts(bb::pim::account::Service::Messages,"sms-mms");

bb::pim::account::AccountKey smsAccountId = 0;
if(!accountListy.isEmpty()) {
    smsAccountId = accountListy.first().id();
    qDebug() << "SMS-MMS account ID:" << smsAccountId;
}
else {
    qWarning() << "Could not find SMS account";
    return;
}



QList<bb::pim::message::MessageContact> participants;
foreach(const QString &phoneNumber, phoneNumbers) {
    bb::pim::message::MessageContact recipient = bb::pim::message::MessageContact(
        -1, bb::pim::message::MessageContact::To,
        phoneNumber, phoneNumber);
    participants.append(recipient);
}

bb::pim::message::ConversationBuilder *conversationBuilder =
    bb::pim::message::ConversationBuilder::create();
conversationBuilder->accountId(smsAccountId);
conversationBuilder->participants(participants);

bb::pim::message::Conversation conversation = *conversationBuilder;
bb::pim::message::ConversationKey conversationId = messageService.save(smsAccountId, conversation);

bb::pim::message::MessageBuilder *builder =
    bb::pim::message::MessageBuilder::create(smsAccountId);
builder->conversationId(conversationId);

builder->addAttachment(bb::pim::message::Attachment("text/plain", "", messageText.toUtf8()));

foreach(const bb::pim::message::MessageContact recipient, participants) {
    builder->addRecipient(recipient);
}

bb::pim::message::Message message = *builder;

messageService.send(smsAccountId, message);

delete builder;
delete conversationBuilder;

}

但是，每次它发送一条新的 SMS 时，它都会在 Text Messages UI 中创建一个新线程。我想知道是否有一种方法可以将新消息添加到已经存在的线程中，该线程将发送到它要发送到的号码？

谢谢！

4

1 回答 1

2

导致此错误的代码方面是

// at top of file
using namespace bb::pim::messages;

ConversationBuilder *conversationBuilder = ConversationBuilder::create();
conversationBuilder->accountId(smsAccountId);
conversationBuilder->participants(participants);

Conversation conversation = *conversationBuilder;
ConversationKey conversationId = messageService.save(smsAccountId, conversation);

这篇文章——按照前面的内容，将创建一个新的对话，participants而不考虑 Hub 中以前存在的对话。

要解决此问题，BlackBerry Cascades PIM MessageService 提供了一个MessageSearchFilter您可以使用它来过滤任何SearchFilterCriteria. 这样使用它……</p> 

//Setup a filter
MessageFilter filter;
//Set our filter to filter conversations with id of the contact
filter.insert(MessageFilter::ContactId, contactId);
//Run filter
filterdConvosKeys = messageService.conversationKeys(smsAccountId, filter);

ConversationKey conversation_id;
//Vars for conversation builder
conversationBuilder->accountId(smsAccountId);
conversationBuilder->participants(participants);

//Get conversation ID for existing conversation, else create new
if (filterdConvosKeys.count() > 1) {
    // go through all conversations for this contact and choose
    // the conversation in which this contact is the sole participant
else if (filterdConvosKeys.count() == 1) {
    conversation_id = filterdConvosKeys[0].toAscii();
} else {
    conversation_id =  messageService.save(smsAccountId, conversation);
}

编辑

尽管原始来源说了什么，但我发现它有点错误。如果您完全按照它所说的那样使用它，如果没有与联系人作为唯一参与者的对话，您将始终以新的对话结束。我尝试在我的 STL100-3 上的 BlackBerry Hub 中使用联系人的电话号码进行搜索，结果我发现许多消息都在同一个对话中。但这意味着如果您按 过滤，可能会返回许多对话MessageFilter::Participants。最好使用 过滤MessageFilter::ContactId。

ps：我对代码块进行了命名空间，所以bb::pim::messages::不再重复。

于 2014-01-04T16:45:31.653 回答