1

调用以下脚本来动态添加 html 输入元素。下面标记的代码(大约 30 行)有两个问题。

1)应该显示两个输入框,当我在第二个输入框(foox1 - “姓氏”)下方添加标记代码时没有显示。

2) 第二个是我需要 id='suggestions' 是动态的,即链接到 foox1。我应该像使用其余代码一样使用 setAttribute ,但我需要先获得 1) 上面的工作。

<script language="javascript">

var x = 1;

function add() {
var fooId = "foo";

for (i=1; i<=2; i++)
  {
    //Create an input type dynamically.
    var element = document.createElement("input");

    //Assign different attributes to the element.
    element.setAttribute("type", fooId+x+i);
    element.setAttribute("name", fooId+x+i);
    element.setAttribute("id", fooId+x+i);

    if(i==1){
           element.setAttribute("value", "First name");
           element.setAttribute("onkeyup", "lookup(this.value);");
           element.setAttribute("onblur", "fill();");

     }
    if(i==2){
          element.setAttribute("value", "Last name");

    }
    var foo = document.getElementById("fooBar");
    foo.appendChild(element);

    /************************************************
    This is where the problem is, in this if statement.  
    This part of the code is required for an autofil in the text box

    ************************************************/

    if(i==1){
        foo.appendChild("<div class='suggestionsBox' id='suggestions' style='display: 
            none;'><img src='upArrow.png' style='position: relative; top: -12px; left: 30px;'         
            alt='upArrow' /><div class='suggestionList' id='autoSuggestionsList'>&nbsp;       </div>    </div>");
    }

    /********************************
    end of code with issues
    ******************************/

    var space = document.createTextNode(" ");
    foo.appendChild(space);  

}
        i++;            
            var element = document.createElement("input");
    element.setAttribute("type", "button");
    element.setAttribute("value", "Remove");
    element.setAttribute("id", fooId+x+i);
    element.setAttribute("name", fooId+x+i);    
    element.setAttribute("onclick", "removeRow(this)");
    foo.appendChild(element);

    var br = document.createElement("br");
    foo.appendChild(br);

    x++;

}
</SCRIPT>
4

2 回答 2

1

您不能.appendChild在以下上下文中使用。.appendChild添加一个节点而不是字符串。

foo.appendChild("<div class='suggestionsBox' id='suggestions' style='display: 
            none;'><img src='upArrow.png' style='position: relative; top: -12px; left: 30px;'         
            alt='upArrow' /><div class='suggestionList' id='autoSuggestionsList'>&nbsp;       </div>    </div>");

它一定要是

foo.innerHTML += "<div class='suggestionsBox' id='suggestions' style='display: none;'><img src='upArrow.png' style='position: relative; top: -12px; left: 30px;' alt='upArrow' /><div class='suggestionList' id='autoSuggestionsList'>&nbsp;  </div>   </div>";

工作演示

编辑:对于您问题的第二部分,您可以id='suggestions_for_' + fooId + x + i在上述声明中执行。(它会产生类似的东西id='suggestions_for_foo11'。)

于 2013-09-01T07:34:46.573 回答
0

你需要结束前两行中的每一行" +

于 2013-09-01T07:16:50.600 回答