0

好吧，我一直在寻找答案，但没有一个对我有用。我有一个按钮，当它被按住时，应该继续在屏幕上移动图像。但由于某种原因，当我点击按钮时，它只会冻结我的 Kindle。我认为线程是问题的一部分，但我不确定。这是代码：

package com.evilsea.darkages;

import android.os.Bundle;
import android.app.Activity;
import android.graphics.Color;
import android.view.MotionEvent;
import android.view.View;
import android.view.View.OnTouchListener;
import android.widget.ImageView;

public class MainActivity extends Activity implements OnTouchListener, Runnable {

ImageView leftImageButton;

boolean leftButtonDown = false;

ImageView knight;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    Thread thread1 = new Thread(this);
    thread1.start();
    this.run();
}

public void addListenerOnLeftButton() {

    leftImageButton = (ImageView) findViewById(R.id.left_button);
    leftImageButton.setOnTouchListener(leftButtonlistener);

    knight = (ImageView) findViewById(R.id.knight_image);

}

OnTouchListener leftButtonlistener = new OnTouchListener() {
    @Override
    public boolean onTouch(View view, MotionEvent event) {
        switch (event.getAction()) {

            case MotionEvent.ACTION_DOWN:
                leftButtonDown = true;
            try {
                while(leftButtonDown) {
                    Thread.sleep(10);
                    moveLeft(5);
                }
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            break;

            case MotionEvent.ACTION_UP:
                leftButtonDown = false;
            break;
        }

        return false;
    }
    };

@Override
public boolean onTouch(View v, MotionEvent event) {
    // TODO Auto-generated method stub
    return false;
}

@Override
public void run() {
    addListenerOnLeftButton();
}

public void moveLeft(int speed) throws InterruptedException {
    knight.setLeft(knight.getLeft() -speed);
}

}

顺便说一句，我刚开始使用 android，所以如果这是一个明显的问题，我很抱歉。谢谢！非常感激。

4

2 回答 2

2

首先，您正在使 UI 线程休眠，这就是您的 UI 冻结的原因。在这里，我创建了一个异步任务，我正在休眠后台线程并在主线程上运行 UI 更新，如下面的 doInBackground 方法所示。这里是您的解决方案-：

public class MainActivity extends Activity {

    private ImageView leftImageButton;
    private boolean leftButtonDown = false;
    private ImageView knight;
    private AsyncTask asyncTask = null;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        leftImageButton = (ImageView) findViewById(R.id.imageView2);
        knight = (ImageView) findViewById(R.id.imageView1);
        leftImageButton.setOnTouchListener(new LeftImageListener());
    }

    public void startTask() {
        asyncTask = new AsyncTask<Void, Void, Void>() {

            @Override
            protected Void doInBackground(Void... params) {
                if (leftButtonDown) {
                    while (leftButtonDown) {
                        try {
                            Thread.sleep(10);
                            runOnUiThread(new Runnable() {

                                @Override
                                public void run() {
                                    try {
                                        moveLeft(5);

                                    } catch (InterruptedException e) {
                                        // TODO Auto-generated catch block
                                        e.printStackTrace();
                                    }

                                }
                            });

                        } catch (InterruptedException e) {
                            e.printStackTrace();
                        }
                    }
                }
                return null;
            }

        }.execute();
    }

    public void moveLeft(int speed) throws InterruptedException {
        knight.setLeft(knight.getLeft() - speed);
    }

    public class LeftImageListener implements OnTouchListener {

        public LeftImageListener() {
            // TODO Auto-generated constructor stub
        }

        @Override
        public boolean onTouch(View v, MotionEvent event) {

            switch (event.getAction()) {
            case MotionEvent.ACTION_DOWN:
                leftButtonDown = true;
                startTask();
                break;
            case MotionEvent.ACTION_UP:
                leftButtonDown = false;
                break;
            default:
                break;
            }

            return true;
        }

    }

}
于 2013-09-01T05:35:15.290 回答
0

创建第二个线程是正确的，但您应该用一些操作填充它，因为您创建的线程是一个空线程:) 并且您不需要在启动线程后调用 run。

感谢 Abhishek Birdawade 为我编写代码 :)

于 2013-08-31T20:34:22.010 回答