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我有一段用于距离计算器的简单代码，我在这里找到了它。

但是，我不知道为什么当我将它上传到我的服务器时它根本不起作用！

这是代码：

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<body>
<?php

    $distances = array();
    $distances[0] = array("id"=>"0","name"=>"Pittsburgh","long"=>"-79.9954","lat"=>"40.4409");
    $distances[1] = array("id"=>"1","name"=>"Las Vegas","long"=>"-94.1024","lat"=>"36.1749");
    $distances[2] = array("id"=>"2","name"=>"Beaumont","long"=>"-79.9954","lat"=>"30.0862");
    $distances[3] = array("id"=>"3","name"=>"South Bend","long"=>"-86.2517","lat"=>"41.673");
    $distances[4] = array("id"=>"4","name"=>"Hampton","long"=>"-76.3447","lat"=>"37.03");
    $distances[5] = array("id"=>"5","name"=>"Savannah","long"=>"-81.0946","lat"=>"32.0728");


    if(getenv("REQUEST_METHOD")=="POST")
    {

        $lon1 = $distances[$from]["long"];
        $lat1 = $distances[$from]["lat"];

        $lon2 = $distances[$to]["long"];
        $lat2 = $distances[$to]["lat"];

        $distance = (3958*3.1415926*sqrt(($lat2-$lat1)*($lat2-$lat1) + cos($lat2/57.29578)*cos($lat1/57.29578)*($lon2-$lon1)*($lon2-$lon1))/180);

        $summary = "Total distance between ".$distances[$from]["name"]." and ".$distances[$to]["name"]." is ".sprintf("%01.02d",$distance)." km";
        $summary.= "<br><br>( $lon1,$lat1 )  ($lon2,$lat2)";
    }

?>
<table width="400" border="0" align="center" cellpadding="0" cellspacing="0">
  <tr>
    <td><form name="form1" method="post" action="">
      <table width="400" border="0" cellpadding="0" cellspacing="0" class="bodytext">
        <tr>
          <td width="166"><select name="from" class="bodytext">
<?php foreach ($distances as $value){?>
<option <?php if($from==$value["id"])print("selected");?> value="<?php print($value["id"]);?>"><?php print($value["name"]);?></option>
<?php }?>
 </select></td>
          <td width="117"><select name="to" class="bodytext">
<?php foreach ($distances as $value){?>
<option <?php if($to==$value["id"])print("selected");?> value="<?php print($value["id"]);?>"><?php print($value["name"]);?></option>
<?php }?>
 </select></td>
          <td width="117"><input name="Submit" type="submit" class="bodytext" value="Calculate"></td>
        </tr>
        <tr>
          <td>&nbsp;</td>
          <td>&nbsp;</td>
          <td>&nbsp;</td>
        </tr>
        <tr>
          <td colspan="3">
<?php   print($summary); ?></td>
          </tr>
      </table>
    </form></td>
  </tr>
</table>
</body></html>

我错过了什么吗？我现在已经更新了代码。最后一个代码是错误的。对于那个很抱歉。

4

1 回答 1

2

问题是提交后如何从表单中获取值。您应该通过获取$_POST数组的值来做到这一点，而不是从具有表单组件名称的变量中。这个：

if(getenv("REQUEST_METHOD")=="POST")
{

    $lon1 = $distances[$from]["long"];
    $lat1 = $distances[$from]["lat"];

    $lon2 = $distances[$to]["long"];
    $lat2 = $distances[$to]["lat"];

    $distance = (3958*3.1415926*sqrt(($lat2-$lat1)*($lat2-$lat1) + cos($lat2/57.29578)*cos($lat1/57.29578)*($lon2-$lon1)*($lon2-$lon1))/180);

    $summary = "Total distance between ".$distances[$from]["name"]." and ".$distances[$to]["name"]." is ".sprintf("%01.02d",$distance)." km";
    $summary.= "<br><br>( $lon1,$lat1 )  ($lon2,$lat2)";
}

应该变成这样：

if(getenv("REQUEST_METHOD")=="POST")
{
    $lon1 = $distances[$_POST["from"]]["long"];
    $lat1 = $distances[$_POST["from"]]["lat"];

    $lon2 = $distances[$_POST["to"]]["long"];
    $lat2 = $distances[$_POST["to"]]["lat"];

    $distance = (3958*3.1415926*sqrt(($lat2-$lat1)*($lat2-$lat1) + cos($lat2/57.29578)*cos($lat1/57.29578)*($lon2-$lon1)*($lon2-$lon1))/180);

    $summary = "Total distance between ".$distances[$from]["name"]." and ".$distances[$to]["name"]." is ".sprintf("%01.02d",$distance)." km";
    $summary.= "<br><br>( $lon1,$lat1 )  ($lon2,$lat2)";
}
于 2013-08-31T17:51:08.567 回答