php - MySQL Where Date (not datetime) as Week of year

Question

我使用 Symfony2 进行了以下查询，我想将字段(2013-08-31) 转换i.fechaInicio为当前周数，以便我可以从当前周获取结果...dateY-m-d

$now = new \DateTime();
$semana = $now->format('W'); // Week Number
$query = $this->getEntityManager()
->createQuery("
        SELECT i
        FROM PgeIncidenciasBundle:Incidencia i
        WHERE i.fechaInicio = :semana // This is wrong because compares
                                      // Y-m-d with W so no results found...
        ")
->setParameters(array(
    'semana' => $semana
))
;
try {
    return $query->getResult();
}
catch (\Doctrine\ORM\NoResultException $e)
{
    return null;
}

Answer 1

使用BETWEEN运算符：

$from = new DateTime;
$from->setIsoDate($from->format('o'), $from->format('W'));
$to = clone $from;
$to->modify('+6 day');

$query = $this->getEntityManager()
    ->createQuery("
        SELECT i
        FROM PgeIncidenciasBundle:Incidencia i
        WHERE i.fechaInicio BETWEEN :from AND :to
    ")
    ->setParameters(array(
        'from' => $from->format('Y-m-d'),
        'to' => $to->format('Y-m-d'),
    ));

Answer 2

找到了一个使用WHERE IN()并生成本周日期数组的解决方案。

public function findCounter()
    {
        $now = new \DateTime();
        $semana = $now->format('Y-m-d');
        $query = $this->getEntityManager()
        ->createQuery("
                SELECT i
                FROM PgeIncidenciasBundle:Incidencia i
                WHERE i.fechaInicio IN (:semana)
                ")
        ->setParameters(array(
            'semana' => $this->week_from_monday($semana)
        ))
        ;
        try {
            return $query->getResult();
        }
        catch (\Doctrine\ORM\NoResultException $e)
        {
            return null;
        }
    }

private function week_from_monday($date) {
    list($year, $month, $day) = explode("-", $date);
    $wkday = date('l',mktime('0','0','0', $month, $day, $year));
    switch($wkday) {
        case 'Monday': $numDaysToMon = 0; break;
        case 'Tuesday': $numDaysToMon = 1; break;
        case 'Wednesday': $numDaysToMon = 2; break;
        case 'Thursday': $numDaysToMon = 3; break;
        case 'Friday': $numDaysToMon = 4; break;
        case 'Saturday': $numDaysToMon = 5; break;
        case 'Sunday': $numDaysToMon = 6; break;
    }
    $monday = mktime('0','0','0', $month, $day-$numDaysToMon, $year);
    $seconds_in_a_day = 86400;
    for($i=0; $i<7; $i++)
    {
    $dates[$i] = date('Y-m-d',$monday+($seconds_in_a_day*$i));
    }
    return $dates;
}