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我使用异步套接字创建了多个客户端服务器。每当我启动 gui 时，由于特定代码服务器 gui 挂起的问题。以下是我的代码

static Socket serverSocket;
static byte[] buffer = new Byte[1024];
public static ManualResetEvent allDone = new ManualResetEvent(false);
private static void StartServer()
{
    byte[] bytes = new Byte[1024];
    IPAddress ipAddress = IPAddress.Parse("127.0.0.1");
    IPEndPoint localEndPoint = new IPEndPoint(ipAddress, 8001);

        serverSocket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp);
        serverSocket.Bind(localEndPoint);
        serverSocket.Listen(100);
        serverSocket.BeginAccept(new AsyncCallback(AcceptCallback), null);

        while (true)
        {
            // Set the event to nonsignaled state.
            allDone.Reset();

            // Start an asynchronous socket to listen for.
            Console.WriteLine("Waiting for a connection...");
            serverSocket.BeginAccept(
               new AsyncCallback(AcceptCallback),
                serverSocket);

            // Wait until a connection is made before tinuing.
            allDone.WaitOne();
        }


}


private static void AcceptCallback(IAsyncResult ar)
{
    allDone.Set();
    try
    {
        Socket clientSocket = serverSocket.EndAccept(ar);

        //var buffer1 = new byte[1024];
        clientSocket.BeginReceive(buffer, 0, buffer.Length, SocketFlags.None, new AsyncCallback(ReceiveCallback), clientSocket);
        serverSocket.BeginAccept(new AsyncCallback(AcceptCallback), null);

    }
    catch (Exception ex)
    {

    }
}


private static void ReceiveCallback(IAsyncResult ar)
{
    try
    {
        int received = 0;
        Socket current = (Socket)ar.AsyncState;
        Console.WriteLine("connected : " + current.RemoteEndPoint.ToString());
        received = current.EndReceive(ar);
        byte[] data = new byte[received];

        if (received == 0)
        {
            return;
        }

        Array.Copy(buffer, data, received);
        string text = Encoding.ASCII.GetString(data);
        Console.WriteLine(text);
        Send(current, "hello");
       /// AppendToTextBox(text);
        buffer = null;
        Array.Resize(ref buffer, current.ReceiveBufferSize);

        current.BeginReceive(buffer, 0, buffer.Length, SocketFlags.None, new AsyncCallback(ReceiveCallback), current);
    }
    catch (Exception ex)
    {

    }
}


        }

每当我单击调用 StartServer 进程的 gui 按钮时，gui 都会挂起，因为 while(true){} 部分。控制台中的代码工作正常。避免这种情况的解决方案是什么？

4

1 回答 1

1

你可以这样做，否则你的 gui 线程将不得不等到无限的while 循环结束；如果以下线程不是您想要的，请考虑添加中断功能。

 using System.Threading;

 Thread th = new Thread(new ThreadStart(delegate
 {
  //while loop
 }));
 th.Start();
于 2013-08-31T12:42:32.463 回答