446

使用 LINQ，List<int>如何从 a 中检索包含重复多次的条目及其值的列表？

4

11 回答 11

754

解决问题的最简单方法是根据元素的值对元素进行分组，如果组中有多个元素，则选择该组的代表。在 LINQ 中，这转换为：

var query = lst.GroupBy(x => x)
              .Where(g => g.Count() > 1)
              .Select(y => y.Key)
              .ToList();

如果您想知道元素重复了多少次，可以使用：

var query = lst.GroupBy(x => x)
              .Where(g => g.Count() > 1)
              .Select(y => new { Element = y.Key, Counter = y.Count() })
              .ToList();

这将返回List匿名类型的 a ，并且每个元素都将具有属性Element和Counter，以检索您需要的信息。

最后，如果您要查找的是字典，则可以使用

var query = lst.GroupBy(x => x)
              .Where(g => g.Count() > 1)
              .ToDictionary(x => x.Key, y => y.Count());

这将返回一个字典，以您的元素作为键，并将其重复次数作为值。

于 2013-08-31T10:58:27.107 回答
179

找出可枚举是否包含任何重复项：

var anyDuplicate = enumerable.GroupBy(x => x.Key).Any(g => g.Count() > 1);

找出可枚举中的所有值是否都是唯一的：

var allUnique = enumerable.GroupBy(x => x.Key).All(g => g.Count() == 1);
于 2014-12-01T17:34:52.323 回答
27

另一种方法是使用HashSet：

var hash = new HashSet<int>();
var duplicates = list.Where(i => !hash.Add(i));

如果您想要重复列表中的唯一值：

var myhash = new HashSet<int>();
var mylist = new List<int>(){1,1,2,2,3,3,3,4,4,4};
var duplicates = mylist.Where(item => !myhash.Add(item)).Distinct().ToList();

这是与通用扩展方法相同的解决方案：

public static class Extensions
{
  public static IEnumerable<TSource> GetDuplicates<TSource, TKey>(this IEnumerable<TSource> source, Func<TSource, TKey> selector, IEqualityComparer<TKey> comparer)
  {
    var hash = new HashSet<TKey>(comparer);
    return source.Where(item => !hash.Add(selector(item))).ToList();
  }

  public static IEnumerable<TSource> GetDuplicates<TSource>(this IEnumerable<TSource> source, IEqualityComparer<TSource> comparer)
  {
    return source.GetDuplicates(x => x, comparer);      
  }

  public static IEnumerable<TSource> GetDuplicates<TSource, TKey>(this IEnumerable<TSource> source, Func<TSource, TKey> selector)
  {
    return source.GetDuplicates(selector, null);
  }

  public static IEnumerable<TSource> GetDuplicates<TSource>(this IEnumerable<TSource> source)
  {
    return source.GetDuplicates(x => x, null);
  }
}
于 2013-10-20T10:00:19.510 回答
14

仅查找重复值：

var duplicates = list.GroupBy(x => x.Key).Any(g => g.Count() > 1);

例如

var list = new[] {1,2,3,1,4,2};

GroupBy将按它们的键对数字进行分组，并与它保持计数（重复的次数）。之后，我们只是检查重复多次的值。

仅查找唯一值：

var unique = list.GroupBy(x => x.Key).All(g => g.Count() == 1);

例如

var list = new[] {1,2,3,1,4,2};

GroupBy将按它们的键对数字进行分组，并与之保持计数（重复的次数）。之后，我们只是检查仅重复一次的值意味着是唯一的。

于 2018-11-09T05:47:20.870 回答
12

你可以这样做：

var list = new[] {1,2,3,1,4,2};
var duplicateItems = list.Duplicates();

使用这些扩展方法：

public static class Extensions
{
    public static IEnumerable<TSource> Duplicates<TSource, TKey>(this IEnumerable<TSource> source, Func<TSource, TKey> selector)
    {
        var grouped = source.GroupBy(selector);
        var moreThan1 = grouped.Where(i => i.IsMultiple());
        return moreThan1.SelectMany(i => i);
    }

    public static IEnumerable<TSource> Duplicates<TSource, TKey>(this IEnumerable<TSource> source)
    {
        return source.Duplicates(i => i);
    }

    public static bool IsMultiple<T>(this IEnumerable<T> source)
    {
        var enumerator = source.GetEnumerator();
        return enumerator.MoveNext() && enumerator.MoveNext();
    }
}

在 Duplicates 方法中使用 IsMultiple() 比 Count() 更快，因为这不会迭代整个集合。

于 2013-08-31T13:28:19.107 回答
6

我创建了一个扩展来响应这个你可以将它包含在你的项目中，我认为当你在 List 或 Linq 中搜索重复项时，这会返回大多数情况。

例子：

//Dummy class to compare in list
public class Person
{
    public int Id { get; set; }
    public string Name { get; set; }
    public string Surname { get; set; }
    public Person(int id, string name, string surname)
    {
        this.Id = id;
        this.Name = name;
        this.Surname = surname;
    }
}


//The extention static class
public static class Extention
{
    public static IEnumerable<T> getMoreThanOnceRepeated<T>(this IEnumerable<T> extList, Func<T, object> groupProps) where T : class
    { //Return only the second and next reptition
        return extList
            .GroupBy(groupProps)
            .SelectMany(z => z.Skip(1)); //Skip the first occur and return all the others that repeats
    }
    public static IEnumerable<T> getAllRepeated<T>(this IEnumerable<T> extList, Func<T, object> groupProps) where T : class
    {
        //Get All the lines that has repeating
        return extList
            .GroupBy(groupProps)
            .Where(z => z.Count() > 1) //Filter only the distinct one
            .SelectMany(z => z);//All in where has to be retuned
    }
}

//how to use it:
void DuplicateExample()
{
    //Populate List
    List<Person> PersonsLst = new List<Person>(){
    new Person(1,"Ricardo","Figueiredo"), //fist Duplicate to the example
    new Person(2,"Ana","Figueiredo"),
    new Person(3,"Ricardo","Figueiredo"),//second Duplicate to the example
    new Person(4,"Margarida","Figueiredo"),
    new Person(5,"Ricardo","Figueiredo")//third Duplicate to the example
    };

    Console.WriteLine("All:");
    PersonsLst.ForEach(z => Console.WriteLine("{0} -> {1} {2}", z.Id, z.Name, z.Surname));
    /* OUTPUT:
        All:
        1 -> Ricardo Figueiredo
        2 -> Ana Figueiredo
        3 -> Ricardo Figueiredo
        4 -> Margarida Figueiredo
        5 -> Ricardo Figueiredo
        */

    Console.WriteLine("All lines with repeated data");
    PersonsLst.getAllRepeated(z => new { z.Name, z.Surname })
        .ToList()
        .ForEach(z => Console.WriteLine("{0} -> {1} {2}", z.Id, z.Name, z.Surname));
    /* OUTPUT:
        All lines with repeated data
        1 -> Ricardo Figueiredo
        3 -> Ricardo Figueiredo
        5 -> Ricardo Figueiredo
        */
    Console.WriteLine("Only Repeated more than once");
    PersonsLst.getMoreThanOnceRepeated(z => new { z.Name, z.Surname })
        .ToList()
        .ForEach(z => Console.WriteLine("{0} -> {1} {2}", z.Id, z.Name, z.Surname));
    /* OUTPUT:
        Only Repeated more than once
        3 -> Ricardo Figueiredo
        5 -> Ricardo Figueiredo
        */
}
于 2016-09-27T11:33:15.497 回答
3

有一个答案，但我不明白为什么不起作用；

var anyDuplicate = enumerable.GroupBy(x => x.Key).Any(g => g.Count() > 1);

在这种情况下，我的解决方案就是这样；

var duplicates = model.list
                    .GroupBy(s => s.SAME_ID)
                    .Where(g => g.Count() > 1).Count() > 0;
if(duplicates) {
    doSomething();
}
于 2020-03-29T16:12:16.017 回答
1

在 MS SQL Server 中检查了 Duplicates 函数的完整 Linq to SQL 扩展集。不使用 .ToList() 或 IEnumerable。这些查询在 SQL Server 中而不是在内存中执行。. 结果仅在内存中返回。

public static class Linq2SqlExtensions {

    public class CountOfT<T> {
        public T Key { get; set; }
        public int Count { get; set; }
    }

    public static IQueryable<TKey> Duplicates<TSource, TKey>(this IQueryable<TSource> source, Expression<Func<TSource, TKey>> groupBy)
        => source.GroupBy(groupBy).Where(w => w.Count() > 1).Select(s => s.Key);

    public static IQueryable<TSource> GetDuplicates<TSource, TKey>(this IQueryable<TSource> source, Expression<Func<TSource, TKey>> groupBy)
        => source.GroupBy(groupBy).Where(w => w.Count() > 1).SelectMany(s => s);

    public static IQueryable<CountOfT<TKey>> DuplicatesCounts<TSource, TKey>(this IQueryable<TSource> source, Expression<Func<TSource, TKey>> groupBy)
        => source.GroupBy(groupBy).Where(w => w.Count() > 1).Select(y => new CountOfT<TKey> { Key = y.Key, Count = y.Count() });

    public static IQueryable<Tuple<TKey, int>> DuplicatesCountsAsTuble<TSource, TKey>(this IQueryable<TSource> source, Expression<Func<TSource, TKey>> groupBy)
        => source.GroupBy(groupBy).Where(w => w.Count() > 1).Select(s => Tuple.Create(s.Key, s.Count()));
}
于 2018-09-11T06:11:43.237 回答
0

LINQ查询：

var query = from s2 in (from s in someList group s by new { s.Column1, s.Column2 } into sg select sg) where s2.Count() > 1 select s2;
于 2020-07-16T10:26:59.830 回答
0

这种不使用组的更简单方法只需获取 District 元素，然后遍历它们并检查它们在列表中的计数，如果它们的计数大于 1，这意味着它出现超过 1 个项目，因此将其添加到 Repeteditemlist

var mylist = new List<int>() { 1, 1, 2, 3, 3, 3, 4, 4, 4 };
            var distList=  mylist.Distinct().ToList();
            var Repeteditemlist = new List<int>();
            foreach (var item in distList)
            {
               if(mylist.Count(e => e == item) > 1)
                {
                    Repeteditemlist.Add(item);
                }
            }
            foreach (var item in Repeteditemlist)
            {
                Console.WriteLine(item);
            }

预期输出：

1 3 4

于 2021-08-08T00:18:41.073 回答
-2

按键删除重复项

myTupleList = myTupleList.GroupBy(tuple => tuple.Item1).Select(group => group.First()).ToList();
于 2021-06-25T12:50:49.330 回答