0

我试图摆脱未定义的索引。每次我在不勾选框的情况下单击提交时，都会收到未定义的索引错误。

<html>
    <head>
        <title>Order</Title>
            <style>
            </style>
        <body>
            <form action = "order.php" method = "post">
                Coffee:<p>
                <input type = "checkbox" value = "coffee" name = "cappuccino"/>Capuccino<br>
</form>
        </body> 
    </head>
</Html>

<?php
    $capuccino = 3.75;
    if(isset($_POST["submit"]))
    {
        if($_POST['cappuccino'] <> 'coffee')
        {
            $capuccino = 0;
        }
    }
?>
4

4 回答 4

1

试试isset喜欢

<?php
    if(isset($_POST["submit"]))
    {
        if(isset($_POST['cappuccino']) && $_POST['cappuccino'] <> 'coffee')
        {
            $capuccino = 0;
        }
    }
?>

您也可以!=改用<>

$_POST['cappuccino'] != 'coffee'
于 2013-08-31T09:51:47.143 回答
1

在 HTML 表单中，如果您不检查值，则不会发布该值。您应该测试它是否首先发布，因此您的 php 代码将类似于：

<?php
if(isset($_POST["submit"]))
{
    if(isset($_POST['cappuccino']) && $_POST['cappuccino'] <> 'coffee')
    {
        $capuccino = 0;
    }
}
?>
于 2013-08-31T09:52:52.080 回答
0

你的条件应该是：

if(array_key_exists('cappuccino', $_POST) && isset($_POST['cappuccino']) && $_POST['cappuccino'] <> 'coffee')
于 2013-08-31T09:53:14.743 回答
0 
    <html>
    <head>
        <title>Order</Title>
            <style>
            </style>
        <body>
            <form action = "order.php" method = "post">
                Coffee:<p>
                <input type = "checkbox" value = "coffee" name = "cappuccino"/>Capuccino<br>
<input type="submit" name="submit" value="Submit" />
</form>
        </body> 
    </head>
</Html>

<?php
    $capuccino = 3.75;
    if(isset($_POST["submit"]))
    {
        if(isset($_POST['cappuccino']) && !empty($_POST['cappuccino']) <> 'coffee')
        {
            $capuccino = 0;
        }
    }
?>
于 2013-08-31T09:53:42.733 回答