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我想按类过滤（显示/隐藏）元素。我想让我们说 5 个过滤器一起工作。

<select id='filter4'>...</select>
<select id='filter5'>...</select>
<select id='filter6'>...</select>
<select id='filter7'>...</select>

和

<select id='filter6' multiple>...</select>

jQuery：

jQuery(document).ready(function ($) {
    $("select").on("change", function () {
        var filterVal = $("select#filter4").val();
        var filterVal2 = $("select#filter5").val();
        var filterVal3 = $("select#filter6").val();
        var filterVal4 = $("select#filter7").val();
        var filterVal5 = $("select#filter8").val();
        var filterSelector = "";
        var filter2Selector = "";
        var filter3Selector = "";
        var filter4Selector = "";
        var filter5Selector = "";

        if (filterVal == "all" && filterVal2 == "all" && filterVal3 == "all" && filterVal4 == "all" && filterVal5 === null) {
            //show all items 
            $(".item").fadeIn("fast");
        } else {
            if (filterVal != "all") {
                filterSelector = "." + filterVal;
            }

            if (filterVal2 != "all") {
                filter2Selector = "." + filterVal2;
            }

            if (filterVal3 != "all") {
                filter3Selector = "." + filterVal3;
            }

            if (filterVal4 != "all") {
                filter4Selector = "." + filterVal4;
            }

            if (filterVal5 !== null) {
                filter5Selector = "." + filterVal5;
            }

            $(".item").hide();
            $(filterSelector + filter2Selector + filter3Selector + filter4Selector + filter5Selector).fadeIn("fast");
        }

    });
});

查看此 jsfiddle 中的所有内容！

前四个单个过滤器可以解决任何问题。选择多个选项时，第五个多选择元素无法正常工作（过滤）。

编辑：需要在全局匹配的 g 修饰符 (/ /g) 的帮助下用点（多个 css 选择器）替换逗号：

$(filter4Selector + filter5Selector.replace(/,/g, ".")).fadeIn("fast");

见http://jsfiddle.net/mahish/dum7n/。

下面的答案提供了同样有效的不同代码！

4

2 回答 2

2

清理您的代码并修复了多个查询。注意：

.class1.class2.class3方法class1 && class2 && class 3

.class1, .class2, .class3方法class1 || class2 || class 3

这是之前评论中混淆的原因。

jQuery(document).ready(function ($) {

    var values = [7, 8];

    $("select").on("change", function () {

        var showAll = true,
            show = [],
            joined;

        $.each(values, function (index, id) {
            var $el = $('#filter' + id),
                multi = $el.attr('multiple'),
                val = $el.val();

            if (multi) {
                if (val !== null) {
                    showAll = false;
                    $.each(val, function (i, v) {
                        show.push( v );
                    });
                }
            } else {
                if (val != 'all') {
                    showAll = false;
                    show.push( val );
                }
            }


        });

        console.log(showAll);
        console.log(show);

        if (showAll) {
            //show all items 
            $(".item").fadeIn("fast");
        } else {

            joined = '.' + show.join('.');

            console.log( joined );

            $(".item").hide();
            $( joined ).fadeIn("fast");
        }

    });

    $.each(values, function (index, id) {
        $('#filter' + id).chosen();
    });


});

http://jsfiddle.net/9SZkr/1/

于 2013-08-31T01:36:51.400 回答
0

用逗号分隔选择器，这应该可以工作（google jQuery multiple selectors for more information）

于 2013-08-31T01:24:54.327 回答