3

我正在尝试在用户定义的范围内创建一系列唯一（非重复）随机数。我设法创建了随机数，但我得到了重复的值。如何确保随机数永远不会重复？

Sub GenerateCodesUser()
    Application.ScreenUpdating = False
    Worksheets("Users").Activate

    Dim MINNUMBER As Long
    Dim MAXNUMBER As Long

    MINNUMBER = 1000
    MAXNUMBER = 9999999

    Dim Row As Integer
    Dim Number As Long
    Dim high As Double
    Dim Low As Double
    Dim i As Integer

    If (CustomCodes.CardNumberMin.Value = "") Then
        MsgBox ("Fill Card Number Field!")
        Exit Sub
    ElseIf (CustomCodes.CardNumberMin.Value < MINNUMBER) Then
        MsgBox ("Card Number Value must be equal or higher then" & MINNUMBER)
        Exit Sub
    End If

    If (CustomCodes.CardNumberMax.Value = "") Then
        MsgBox ("Fill Card Number Field!")
        Exit Sub
    ElseIf (CustomCodes.CardNumberMax.Value > MAXNUMBER) Then
        MsgBox ("Card Number Value must be equal or higher then " & MAXNUMBER)
        Exit Sub
    End If

    Low = CustomCodes.CardNumberMin.Value
    high = CustomCodes.CardNumberMax.Value '<<< CHANGE AS DESIRED

    If (Low < 1000) Then
        'break
    End If

    For i = 1 To Cells(1, 1).End(xlToRight).Column
        If InStr(Cells(1, i), "CardNumber") Then
            Row = 2
            While Cells(Row, 1) <> 0
                Do
                    Number = ((high - Low + 1) * Rnd() + Low)
                Loop Until Number > Low
                Cells(Row, i) = Number
                Row = Row + 1
            Wend
        End If
    Next

    Application.ScreenUpdating = True
End Sub
4

4 回答 4

8

这是保证唯一整数随机数的方法。内联注释描述了该方法。

Function UniuqeRandom(Mn As Long, Mx As Long, Sample As Long) As Long()
    Dim dat() As Long
    Dim i As Long, j As Long
    Dim tmp As Long

    ' Input validation checks here
    If Mn > Mx Or Sample > (Mx - Mn + 1) Then
        ' declare error to suit your needs
        Exit Function
    End If

    ' size array to hold all possible values
    ReDim dat(0 To Mx - Mn)

    ' Fill the array
    For i = 0 To UBound(dat)
        dat(i) = Mn + i
    Next

    ' Shuffle array, unbiased
    For i = UBound(dat) To 1 Step -1
        tmp = dat(i)
        j = Int((i + 1) * Rnd)
        dat(i) = dat(j)
        dat(j) = tmp
    Next

    'original biased shuffle
    'For i = 0 To UBound(dat)
    '    tmp = dat(i)
    '    j = Int((Mx - Mn) * Rnd)
    '    dat(i) = dat(j)
    '    dat(j) = tmp
    'Next

    ' Return sample
    ReDim Preserve dat(0 To Sample - 1)
    UniuqeRandom = dat
End Function

像这样使用它

Dim low As Long, high As Long

Dim rng As Range
Dim dat() As Long

Set rng = Range(Cells(1, 1), Cells(1, 1).End(xlToRight))
dat = UniuqeRandom(low, high, rng.Columns.Count)
rng.Offset(1, 0) = dat

注意：请参阅这篇关于随机偏差的维基百科文章

编辑修复了一个偏见来源。Rnd（基于 32 位种子）和模偏差的固有限制仍然存在。

于 2013-08-31T00:54:23.747 回答
2

我看到你有一个公认的答案，但不管它的价值是什么，都是我在这个问题上的尝试。这个使用布尔函数而不是数值数组。它非常简单但速度很快。我并不是说它的优点是完美的，它是一个有效的解决长期数字的方法，因为你只检查你已经选择和保存的数字，不需要一个潜在的大数组来保存这些值你已经拒绝了，所以它不会因为数组的大小而导致内存问题。

Sub UniqueRandomGenerator()
Dim N As Long, MaxNum As Long, MinNum As Long, Rand As Long, i As Long

MinNum = 1        'Put the input of minimum number here
MaxNum = 100      'Put the input of maximum number here
N = MaxNum - MinNum + 1

ReDim Unique(1 To N, 1 To 1)

For i = 1 To N
Randomize         'I put this inside the loop to make sure of generating "good" random numbers
    Do
        Rand = Int(MinNum + N * Rnd)
        If IsUnique(Rand, Unique) Then Unique(i, 1) = Rand:  Exit Do
    Loop
Next
Sheet1.[A1].Resize(N) = Unique
End Sub

Function IsUnique(Num As Long, Data As Variant) As Boolean
Dim iFind As Long

On Error GoTo Unique
iFind = Application.WorksheetFunction.Match(Num, Data, 0)

If iFind > 0 Then IsUnique = False: Exit Function

Unique:
    IsUnique = True
End Function
于 2016-08-12T05:38:20.123 回答
0 
Function RandLotto(Bottom As Integer, Top As Integer, _

                    Amount As Integer) As String

    Dim iArr As Variant

    Dim i As Integer

    Dim r As Integer

    Dim temp As Integer



    Application.Volatile



    ReDim iArr(Bottom To Top)

    For i = Bottom To Top

        iArr(i) = i

    Next i



    For i = Top To Bottom + 1 Step -1

        r = Int(Rnd() * (i - Bottom + 1)) + Bottom

        temp = iArr(r)

        iArr(r) = iArr(i)

        iArr(i) = temp

    Next i



    For i = Bottom To Bottom + Amount - 1

        RandLotto = RandLotto & " " & iArr(i)

    Next i



    RandLotto = Trim(RandLotto)



End Function
于 2016-12-04T09:44:43.313 回答
0

它完美地工作：

Option Base 1
Public Function u(a As Variant, b As Variant) As Variant
 Application.Volatile
 Dim k%, p As Double, flag As Boolean, x() As Variant
    k = 1
  flag = False
  ReDim x(1)
   x(1) = Application.RandBetween(a, b)
  Do Until k = b - a + 1

   Do While flag = False
   Randomize
    p = Application.RandBetween(a, b)
     'Debug.Assert p = 2
    resultado = Application.Match(p, x, False)
     If IsError(resultado) Then
      k = k + 1
      ReDim Preserve x(k)
      x(k) = p
       flag = True
      Else
       flag = False
      End If
   Loop
   flag = False
  Loop
  u = x
End Function
于 2017-03-17T22:59:51.940 回答