1

为什么我在运行以下命令时从未收到 readyReadStandardOutput 信号？

import os, sys, textwrap

from PyQt4 import QtGui, QtCore

out_file = open("sleep_loop.py", 'w')
out_file.write(textwrap.dedent("""
    import time

    while True:
        print "sleeping..."
        time.sleep(1)"""))
out_file.close()

def started():
    print "started"

def on_error(error):
    errors = ["Failed to start", "Crashed", "Timedout", "Read error", 
              "Write Error", "Unknown Error"]
    print "error: ", errors[error]              

def on_state_change(new_state):
    states = ["Not running", "Starting", "Running"]
    print "new state: ", states[new_state]

def on_out():
    print "got out"

proc = QtCore.QProcess()
sig = QtCore.SIGNAL
proc.connect(proc, sig("started()"), started)
proc.connect(proc, sig("error(ProcessError)"), on_error)
proc.connect(proc, sig("readyReadStandardOutput()"), on_out)
proc.connect(proc, sig("stateChanged(ProcessState)"), 
             on_state_change)
proc.start("python sleep_loop.py")

app = QtGui.QApplication(sys.argv)
widget = QtGui.QWidget()
widget.show()
app.exec_()

proc.close()
4

1 回答 1

4

这里有两个问题：

  1. 您应该在创建其他所有内容之前创建 QApplication 实例。
  2. 您的子进程正在缓冲其输出。

这是固定代码，仅更改了两行：

  1. app = QApplication之前搬过proc = QProcess
  2. 子进程现在有sys.stdout.flush()

现在一切都按您的预期进行：

import os, sys, textwrap

from PyQt4 import QtGui, QtCore

out_file = open("sleep_loop.py", 'w')
out_file.write(textwrap.dedent("""
    import time, sys

    while True:
        print "sleeping..."
        sys.stdout.flush()
        time.sleep(1)"""))
out_file.close()

def started():
    print "started"

def on_error(error):
    errors = ["Failed to start", "Crashed", "Timedout", "Read error", 
              "Write Error", "Unknown Error"]
    print "error: ", errors[error]              

def on_state_change(new_state):
    states = ["Not running", "Starting", "Running"]
    print "new state: ", states[new_state]

def on_out():
    print "got out"

app = QtGui.QApplication(sys.argv)
proc = QtCore.QProcess()
sig = QtCore.SIGNAL
proc.connect(proc, sig("started()"), started)
proc.connect(proc, sig("error(ProcessError)"), on_error)
proc.connect(proc, sig("readyReadStandardOutput()"), on_out)
proc.connect(proc, sig("stateChanged(ProcessState)"), 
             on_state_change)
proc.start("python sleep_loop.py")

widget = QtGui.QWidget()
widget.show()
app.exec_()

proc.close()
于 2009-12-06T07:40:12.133 回答