0

我一直在尝试使用SELECT语句计算表格。我有一张这样的桌子：

--------------------------------------------------------------
AgentID     |      Date      |  Incurred     |    FallOffDate
==============================================================
kegomez     |   2012-11-19   |     2.0       |    2013-11-19
kegomez     |   2012-11-24   |     0.5       |    2013-11-24
kegomez     |   2013-01-21   |     2.0       |    2014-01-21
kegomez     |   2013-08-18   |     2.0       |    2014-08-18

我试图在选择期间进行计算，并可能创建一个视图，但到目前为止还没有运气。最后，表格将如下所示。

--------------------------------------------------------------
AgentID     |      Date      |  Incurred     |    90    |    180    |   Total    |    FallOffDate
==============================================================
kegomez |   2012-11-19   |     2.0       |    2.0   |    2.0    |   2.0      |    2013-11-19
kegomez |   2012-11-24   |     0.5       |    0.5   |    0.5    |   2.5      |    2013-11-24
kegomez |   2013-01-21   |     2.0       |    1.0   |    0.0    |   2.5      |    2014-01-21
kegomez |   2013-08-18   |     2.0       |    2.0   |    2.0    |   4.5      |    2014-08-18

总计列使用前一行的值来计算其值。例如，第 4 行中的日期将需要引用第 3 行中的日期，以查看日期是否更大。我需要用子查询试试这个吗？这最终将如何运作是，如果不再发生，代理将每 90 天到 180 天损失 1 分。因此，我需要引用其他行的原因。如果它有助于此数据当前位于 Excel 中，但变得太大而无法管理，我们需要将其移至性能更好的地方。

SELECT AgentID, Date, Incurred, 
    @90 := IF(Date<=CURDATE()-90 AND @r=0, Incurred-1.0, IF(Difference>90, Incurred-1, Incurred)) AS 90Day, 
    @180 := IF(Date<=CURDATE()-90 AND @r=0, Incurred-1.0, IF(Difference>180, Incurred-2, @90)) AS 180Day, 

    @Total := IF(@180<0,0,IF(FallOffDate<=CURDATE(),0, @180)) AS Total,

    FallOffDate 

FROM (SELECT  mo.AgentID, mo.Incurred, FallOffDate, 
        @r AS LEAD_date,
        DATEDIFF(@r,Date) AS Difference,
        (@r := Date) AS Date

FROM    (
        SELECT  m.*
        FROM    (
                SELECT  @_date = NULL
                ) VARIABLE,
                attendance m
        ORDER BY
                AgentID, Date DESC 
        ) mo
WHERE  (CASE WHEN @_date IS NULL OR @_date <> date THEN @r := NULL ELSE NULL END IS NULL)
        AND (@_date := date) IS NOT NULL) T
ORDER BY AgentID, Date;
4

1 回答 1

0

是的，您需要使用子查询来执行此操作，尝试使用类似这样的方法（如果您希望第 4 行访问第 3 行中的日期）：

SELECT  mo.AgentID, mo.date,
        @r AS 'LAG(date)',
        (case when @r<Date then 'YES' when @r is null then 'IS NULL' else 'NO' end) 'Is Bigger',
        (@r := Date) AS Date

FROM    (
        SELECT  m.*
        FROM    (
                SELECT  @_date = NULL
                ) variable,
                data m
        ORDER BY
                AgentID 
        ) mo
WHERE  (CASE WHEN @_date IS NULL OR @_date <> date THEN @r := NULL ELSE NULL END IS NULL)
        AND (@_date := date) IS NOT NULL

你可以在这里看到一个工作演示

或者，如果您希望第 3 行可以访问第 4 行中的日期，您可以尝试此查询

SELECT AgentID,date,LEAD_date,concat(Difference,' days') FROM
(SELECT  mo.AgentID, 
        @r AS LEAD_date,
        DATEDIFF(@r,Date) as Difference,
        (@r := Date) AS Date

FROM    (
        SELECT  m.*
        FROM    (
                SELECT  @_date = NULL
                ) variable,
                data m
        ORDER BY
                AgentID,date desc 
        ) mo
WHERE  (CASE WHEN @_date IS NULL OR @_date <> date THEN @r := NULL ELSE NULL END IS NULL)
        AND (@_date := date) IS NOT NULL) T
order by AgentID,date;

你可以在这里看到一个工作演示

于 2013-08-31T00:01:29.767 回答