-1
cj=http.cookiejar.CookieJar()
opener=build_opener(HTTPCookieProcessor(cj))
data={'uid' : uid , 'password' : password }   #uid is username to the website
data=urllib.parse.urlencode(data)
data=data.encode(encoding='utf-8')
url='http://202.117.120.37/xdjwWebNew/Servlet/UsersControl' # url is a link to a specific page
request=Request(url,data)
response=opener.open(request)
response.geturl()

它输出:

'http://docs.python.org/2/library/urllib2.html?highlight=urllib'

我不知道有什么问题。任何建议都会有所帮助。

4

1 回答 1

0

你在寻找它输出什么?如果您想要链接中的 html 页面,请使用response.read(). 通过文档

This supports the following methods: read(), readline(), readlines()...
...these methods have the same interface as for file objects

The geturl() method returns the real URL of the page.
于 2013-08-30T16:43:49.327 回答