4

我有以下身份验证处理程序:

class LoginAuthSuccessHandler implements AuthenticationSuccessHandlerInterface, AuthenticationFailureHandlerInterface
{
    private $router;
    private $container;

    /**
    * Constructor
    * @param RouterInterface   $router
    */
    public function __construct(RouterInterface $router, $container)
    {
        $this->router = $router;
        $this->container = $container;
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token)
    {
        if ($request->isXmlHttpRequest()) {
            $user =  $this->container->get('security.context')->getToken()->getUser();
            $result = array('success' => true, 'user' => $user);
            return new Response(json_encode($result));
        } else {
            $route = $this->router->generate('ShopiousMainBundle_profile');

            $referrer_url = $request->server->get('HTTP_REFERER');
            if (strstr($referrer_url, '/items/')) {
                 $route = $referrer_url;
            }

            return new RedirectResponse($route);
        }
    }

    public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
    {
        if ($request->isXmlHttpRequest()) {
            $result = array('success' => false, 'message' => $exception->getMessage());
            return new Response(json_encode($result));
        } else {
            // Handle non XmlHttp request here
        }
    }
}

为什么会这样:

$user =  $this->container->get('security.context')->getToken()->getUser();

返回空?此时我如何获得经过身份验证的用户?

4

4 回答 4

8

您应该使用$token您收到的变量作为参数,而不是$this->container->get('security.context')->getToken().

$user = $token->getUser();
于 2013-08-30T16:14:44.480 回答
3
public function onAuthenticationSuccess(Request $request, TokenInterface $token)
{
    $user = $token->getUser();
}

就这样 ;)

于 2016-10-06T07:20:24.013 回答
0

也许你没有在 security.yml 中设置你的提供者。

security:
 provider:
  example:
   entity: {class Acme\AuctionBundle\Entity\User, property: username}

用你的替换 Bundle 和实体。

于 2013-08-30T15:04:08.880 回答
0

我发现的唯一方法是注入 entityManager,

calls:
    - [setEntityManager,[@doctrine.orm.entity_manager]]

使用该用户名从请求中获取用户名并查询用户。

$userRepo->findByEmail($request->get('_username'));
于 2015-11-03T22:24:08.730 回答