python - Python提取包含2个单词的句子

Question

我有这个链接中讨论的相同问题Python extract sentence contains word，但不同之处在于我想在同一个句子中找到 2 个单词。我需要从包含 2 个特定单词的语料库中提取句子。有人可以帮助我吗？

Answer 1

将TextBlob包与 Python 的内置sets一起使用会很简单。

基本上，遍历文本中的句子，并检查句子中的单词集与搜索词之间是否存在交集。

from text.blob import TextBlob

search_words = set(["buy", "apples"])
blob = TextBlob("I like to eat apple. Me too. Let's go buy some apples.")
matches = []
for sentence in blob.sentences:
    words = set(sentence.words)
    if search_words & words:  # intersection
        matches.append(str(sentence))
print(matches)
# ["Let's go buy some apples."]

更新：或者，更 Python 地，

from text.blob import TextBlob

search_words = set(["buy", "apples"])
blob = TextBlob("I like to eat apple. Me too. Let's go buy some apples.")
matches = [str(s) for s in blob.sentences if search_words & set(s.words)]
print(matches)
# ["Let's go buy some apples."]

Answer 2

如果这是你的意思：

import re
txt="I like to eat apple. Me too. Let's go buy some apples."
define_words = 'some apple'
print re.findall(r"([^.]*?%s[^.]*\.)" % define_words,txt)  

Output: [" Let's go buy some apples."]

您也可以尝试：

define_words = raw_input("Enter string: ")

检查句子是否包含定义的单词：

import re
txt="I like to eat apple. Me too. Let's go buy some apples."
words = 'go apples'.split(' ')

sentences = re.findall(r"([^.]*\.)" ,txt)  
for sentence in sentences:
    if all(word in sentence for word in words):
        print sentence

Answer 3

我想你想要一个使用 nltk 的答案。而且我猜这两个词不需要是连续的吧？

>>> from nltk.tokenize import sent_tokenize, word_tokenize
>>> text = 'I like to eat apple. Me too. Let's go buy some apples.'
>>> words = ['like', 'apple']
>>> sentences = sent_tokenize(text)
>>> for sentence in sentences:
...   if (all(map(lambda word: word in sentence, words))):
...      print sentence
...
I like to eat apple.