wcf - WCF RESTful 控制台托管，返回 400 错误请求

Question

学习 WCF RESTful，在控制台中托管，

我的步骤：

1. 创建示例模型
2. 创建服务合同
3. 创建服务
4. 在控制台中托管此服务。
5. 运行这个主机，看起来不错。
6. 创建一个winform，通过json post使用服务地址到服务主机。
7. 我希望它会工作，但返回 http 400。

我尝试了 WCF（不是 REST）控制台托管的 WebAPI，步骤一切正常。

最后，stackoverflow.com

请帮忙

楷模

[Serializable]
public abstract class Building
{
    public Manufacturer Manufacturer { get; set; }
}

[Serializable]
public class Manufacturer
{
    public string Name { get; set; }

    public string Telephone { get; set; }
}

[Serializable]
public class Furniture : Building
{
    public string Name { get; set; }
}

[Serializable]
public class Reception
{
    public int Floor { get; set; }

    public int Number { get; set; }
}

[Serializable]
public class Room : Building
{
    public string Number { get; set; }

    public List<Furniture> Furnitures { get; set; }
}

[Serializable]
public class Hotel : Building
{
    public Guid Guid { get; set; }

    public List<Reception> Receptions { get; set; }

    public List<Room> Rooms { get; set; }

    public string Name { get; set; }

    public string Address { get; set; }
} 

合同

[ServiceContract]
public interface IHotel
{
    // Create objct Hotel
    [OperationContract]
    [WebInvoke(UriTemplate = "", Method = "POST", RequestFormat= WebMessageFormat.Json, ResponseFormat=WebMessageFormat.Json)]
    bool Create(Hotel hotel);
}

服务

public class HotelService : I Hotel
{
    public bool Build(Models.Hotel hotel)
    {
        if (hotel == null)
            return false;

        // codes here is object hotel(EF) creation, test OK
        return true;
    }
}

主机（控制台）

WebServiceHost serviceHost = new WebServiceHost(typeof(Demo.Services.HotelService), new Uri("http://192.168.1.101/HotelService"));
ServiceEndpoint endpoint = serviceHost.AddServiceEndpoint(typeof(Demo.Contracts.IHotel), new WebHttpBinding(), "");
ServiceDebugBehavior sdb = serviceHost.Description.Behaviors.Find<ServiceDebugBehavior>();
sdb.HttpHelpPageEnabled = false;

Console.WriteLine("Starting Service...");
// start service
serviceHost.Open();
Console.WriteLine("Started, press RETURN to exit.");
Console.ReadLine();
serviceHost.Close();

客户端(Winform)

呼叫者

public bool BuildHotel(string json)
{
    WebRequest request = HttpWebRequest.Create("http://192.168.1.101/HotelService");

    request.ContentType = "application/json";

    byte[] data = Encoding.UTF8.GetBytes(json);
    request.ContentLength = data.Length;
    Stream requestStream = request.GetRequestStream();
    requestStream.Write(data, 0, data.Length);
    requestStream.Close();

    WebResponse response = request.GetResponse(); // 400 throwed here
    Stream responseStream = response.GetResponseStream();
    StreamReader responseStreamReader = new StreamReader(responseStream);
    string result = responseStreamReader.ReadToEnd();

    return true;
}

'bool BuildHotel(string)' 的 Json 字符串

{
    "Guid":"ea59c011-d656-4870-b29b-30a44e668560",
    "Receptions":[
        {"Floor":1,"Number":1},
        {"Floor":2,"Number":2}
    ],
    "Rooms":[
        {
            "Number":"c",
            "Furnitures":[
                {"Name":"1","Manufacturer":{"Name":"1","Telephone":"1"}},
                {"Name":"2","Manufacturer":{"Name":"2","Telephone":"2"}}
            ],
            "Manufacturer":{"Name":"c","Telephone":"c"}
        }
    ],
    "Name":"x",
    "Address":"x",
    "Manufacturer":{"Name":"x","Telephone":"x"}
}

Answer 1

它需要这样的 JSON：

{" k_BackingField":{" k_BackingField":"4"," k_BackingField":"4"}," k_BackingField":"x"," k_BackingField":"ea59c011-d656-4870-b29b-30a44e668560 "," k_BackingField":"x"," k_BackingField":[{" k_BackingField":1," k_BackingField":1},{" k_BackingField":2," k_BackingField":2}], " k_BackingField":[{" k_BackingField":{" k_BackingField":"3"," k_BackingField":"3"}," k_BackingField":[{" k_BackingField":{" k_BackingField":"1"," k_BackingField":"1"}," k_BackingField":"1"},{" k_BackingField":{" k_BackingField":"2"," k_BackingField":"2"}, “k_BackingField":"2"}],"k__BackingField":null}]}

要更改它，您可以使用 DataContract 和 DataMember 属性标记所有数据合同：

    [DataContract]
    public abstract class Building
    {
        [DataMember]
        public Manufacturer Manufacturer { get; set; }
    }

在这种情况下，它将理解您在问题中给我们的 json 并成功处理它。