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我有一个像这样通过 JQuery 制作的对话框

    <div class ="editable" id="div_David L. Kirp[instructor_status]"contenteditable="1">
        <span class="text-error">Error: More than one user with same fname and lname</span<br/>
            Users:<br/>
        <span class="multiple-users">
                &nbsp[CLICK HERE] Instructor ID: 65, Common Name: David Kirp</span<br/>  
        <span class="multiple-users">
                &nbsp[CLICK HERE] Instructor ID: 17210, Common Name: David L. Kirp</span><br/><div class="update-dialog" title="Update Common Name">Which instructor do you want to update?<p><input type="radio" id="instructor_65" name="instructor" value="65"/><label for="instructor_65">        
                Instructor ID: 65, Common Name: David Kirp
            </label></p>
            <p><input type="radio" id="instructor_17210" name="instructor" value="17210"/>
<label for="instructor_17210">        
            Instructor ID: 17210, Common Name: David L. Kirp
            </label></p>Which common name do you want to assign the instructor?<p><input type="radio" id="commonName_65" name="common_name" value="David Kirp"/><label for="commonName_65">
            David Kirp
            </label></p><p><input type="radio" id="commonName_17210" name="common_name" value="David L. Kirp"/><label for="commonName_17210">
            David L. Kirp
            </label></p></div><button class="update-button" type="button">Update Common Name of an Instructor</button></div>

<script>
$("div.update-dialog").dialog({
                autoOpen: false,
                dialogClass: 'dialogStyle',
                resizable: false,
                modal: true,
                buttons: {
                    "Update": function() {
                    //$.load('update_common_name.php', 
                        $( this ).dialog( "close" );
                    },
                    Cancel: function() {
                        $( this ).dialog( "close" );
                    }
                }
           });



         $('div.editable').on('click', '.update-button', function () {
            $(".update-dialog").dialog("open");

         }); 

and I want it so that when I click on one of the radios, it will update the existing values to variables instructor_id and common_name (I eventually want to make an ajax request with them), like so: 

$('input:radio').change(function () {        
            instructor_id = $(this).closest('input[name=instructor]:checked').val();
            common_name = $(this).closest('input[name=common_name]:checked').val();

            // alert is for testing
            alert(instructor_id + common_name);
}); 
</script>

但是，当我对其进行测试时，警报消息返回类似“65undefined”和“undefinedDavid L. Kirp”而不是“65David L. Kirp”，这表明并非两个变量都被初始化。我怎样才能解决这个问题？

4

1 回答 1

1

在您的情况下，该错误是完全明智的，因为当您更改时instructor-$(this).closest('input[name=instructor]:checked')为您提供选中的收音机，但$(this).closest('input[name=common_name]:checked')由于common_name收音机不是instructor. 它也可能以其他方式发生，如果您选择一个common_name教练会给undefined

尝试（在您从两组值中选择值之前，这仍然可能为其中一个字段提供未定义的值）

$('input:radio').change(function () {
    var instructor_id = $(this).closest('.update-dialog').find('input[name=instructor]:checked').val();
    var common_name = $(this).closest('.update-dialog').find('input[name=common_name]:checked').val();

    // alert is for testing
    alert(instructor_id + common_name);
});

演示：小提琴

于 2013-08-30T00:02:35.810 回答