0

我正在尝试使用以下代码运行一个简单的like子句...

Message.where('to LIKE ?', '%hi')

我的模型类如下...

类消息 < ActiveRecord::Base

attr_accessor :from, :error_messages, :use_background_job, :to
attr_accessible :status, :to, :from, :cc, :bcc, :subject, :body, :error_messages, :use_background_job

我正在使用 activerecord 和 activerecord-oracle_enhanced-adapter gem。但是我收到以下错误...

  ←[1m←[36mMessage Load (161.1ms)←[0m  ←[1mSELECT "MESSAGES".* FROM "MESSAGES" WHERE (to LIKE 'hi')←[0m
ActiveRecord::StatementInvalid: OCIError: ORA-00936: missing expression: SELECT "MESSAGES".* FROM "MESSAGES"  WHERE (to LIKE 'hi')
        from stmt.c:230:in oci8lib_191.so
        from c:/RailsInstaller/Ruby1.9.3/lib/ruby/gems/1.9.1/gems/ruby-oci8-2.1.5-x86-mingw32/lib/oci8/cursor.rb:126:in `exec'

这是 Oracle 问题还是我的 like 子句语法不正确？

4

2 回答 2

1

Looks like "to" is a Oracle Keyword.

Try this

Message.where('"to" LIKE ?', '%hi')

Oracle uses double quotes to escape keywords

于 2013-08-29T18:58:18.570 回答
1

尝试使用Message.where('messages.to LIKE ?', '%hi'). 我认为'to'是sql中的保留关键字。

于 2013-08-29T19:01:31.380 回答