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我在我的 symfony2 项目中使用了学说。

我有一个桌子事件和一张桌子照片。一个事件可以有一张或多张照片，一张照片与一个事件相关。

这是我的 dql 查询之一：

    $dql = "
    SELECT e, (e.views * 0.1) + (e.likes * 0.9) as ratingEvent
    FROM WevseenMainBundle:Event e
    INNER JOIN e.photos p
    INNER JOIN e.firstPhoto fp
    WHERE fp.date BETWEEN :dateA AND :dateB
    AND p.lat BETWEEN :latA AND :latB
    AND ( p.lng > :lngA AND p.lng < :lngB )
    AND e.status = 'open'
    GROUP BY e
    HAVING COUNT(p.id) >= :minCountPhotos
    ORDER BY ratingEvent DESC
    ";

    $query = $em->createQuery($dql)
    ->setParameters($parameters)
    ->setFirstResult($firstEntry) // 0
    ->setMaxResults($numberOf); // 10

    $paginatorEvents = new Paginator($query, true);

对于 11500 个事件和 160 000 张照片，查询非常慢（超过 10 秒），它来自

GROUP BY e
HAVING COUNT(p.id) >= :minCountPhotos

没有这个，它很快。

我检查了 sf2 分析器，它说：

SELECT count(DISTINCT e0_.id) AS sclr0 FROM Event e0_ INNER JOIN Photo p1_ ON e0_.id = p1_.event_id INNER JOIN Photo p2_ ON e0_.firstPhoto_id = p2_.id WHERE p2_.date BETWEEN ? AND ? AND p1_.lat BETWEEN ? AND ? AND (p1_.lng > ? AND p1_.lng < ?) AND e0_.status = 'open' GROUP BY e0_.id, e0_.name, e0_.description, e0_.nb_photos, e0_.views, e0_.viewsEventPhotos, e0_.votes, e0_.rating, e0_.likes, e0_.up, e0_.down, e0_.status, e0_.end, e0_.time, e0_.averageTimeEvent, e0_.averageTimePhotos, e0_.averageTimeEventAndPhotos, e0_.needInstagramUpdate, e0_.origin, e0_.featured, e0_.firstPhoto_id HAVING COUNT(p1_.id) >= ?
Parameters: [Object(DateTime), Object(DateTime), '-42.93442389074508', '73.48078267112892', '-180', '180', '2']

Time: 2029.33 ms

    SELECT DISTINCT e0_.id AS id0, e0_.views * 1 + e0_.likes * 0 AS sclr1 FROM Event e0_
INNER JOIN Photo p1_ ON e0_.id = p1_.event_id INNER JOIN Photo p2_ ON e0_.firstPhoto_id = p2_.id WHERE p2_.date BETWEEN ? AND ? AND p1_.lat BETWEEN ? AND ? AND (p1_.lng > ? AND p1_.lng < ?) AND e0_.status = 'open' GROUP BY e0_.id, e0_.name, e0_.description, e0_.nb_photos, e0_.views, e0_.viewsEventPhotos, e0_.votes, e0_.rating, e0_.likes, e0_.up, e0_.down, e0_.status, e0_.end, e0_.time, e0_.averageTimeEvent, e0_.averageTimePhotos, e0_.averageTimeEventAndPhotos, e0_.needInstagramUpdate, e0_.origin, e0_.featured, e0_.firstPhoto_id HAVING COUNT(p1_.id) >= ? ORDER BY sclr1 DESC LIMIT 10 OFFSET 0

Time: 6179.01 ms

这是两个需要时间的查询。我该如何改进呢？

更新，解决方案：

改变了

GROUP BY e

和

GROUP BY e.id
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1 回答 1

1

只有在您迭代分页器时才会执行您的请求。您应该复制翻译后的 SQL 请求并在 Doctrine 之外对其进行分析，可能需要 8 秒才能执行。一旦您将一些明智选择的索引添加到您的表中，它可能会更快。

于 2013-08-29T14:45:49.163 回答