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我正在尝试通过查看 CategoryBusinessMapping 和 Review Rating 表来检索 CategoryID 和 CategoryName。我正在尝试检索以下类别表的数据：

Category     ParentCategoryID     CategoryName
1            null                 Education
2            1                    School
3            null                 Health
4            3                    Doctors
5            1                    Colleges

我有Business表，其中包含 BusinessID 和 BusinessName 以及 BusinessDescription，如下所示：

BusinessID     BusinessName     BusinessDescription
YP00001        XYZ              ABCD
YP00002        ABC              XYZA

我有这样的CategoryBusinessMapping表：

MappingID     CategoryID     BusinessID
1             1              YP00001
2             2              YP00001
3             5              YP00001
4             3              YP00002
5             4              YP00002

我有这个映射表来映射不同的类别与业务。我也有这样的评级表：

RatingID     BusinessID
1            YP00001
2            YP00001
3            YP00001
4            YP00002
5            YP00002

在此表中，我假设具有相同 BusinessID 的记录属于最流行的业务。这意味着，在上面 ID = YP00001 的业务 ABCD 中，Rating 表中有四条记录。因此，它属于最受欢迎的业务。同样，YP00002 位于 YP00001 之后。通过按降序查看最受欢迎的业务，我想检索 CategoryName 和 CategoryID。我已尝试仅从评级表中检索：

select   Distinct ReviewRating.BusinessID
         ,Count(*)as Rating
from     YP.utblYPReviewRatingDtls as ReviewRating
group by ReviewRating.BusinessID 
order by Rating desc

我试过这个：

  SELECT  distinct c.CategoryName, b.BusinessID
    FROM Category c
     INNER JOIN categoryBusinessMapping  cbm
     ON (c.CategoryID=cbm.CategoryID)
     INNER JOIN Business b 
    ON (cbm.BusinessID=b.BusinessID)
     LEFT JOIN Rating  r 
     ON (cbm.BusinessID=r.BusinessID)
     where c.ParentCategoryID is null

但我得到的结果是多余的。我还从查询中删除了 BusinessID，我得到了结果，但结果不正确。如何消除冗余并获得正确的输出？

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1 回答 1

2

使用join并 BusinessID从评分表中计算并订购您的结果

SELECT c.*, COUNT(r.BusinessID) AS bcount FROM Category  c
INNER JOIN CategoryBusinessMapping  cbm ON (c.Category=cbm.CategoryID)
INNER JOIN Business b ON (cbm.BusinessID=b.BusinessID)
LEFT JOIN Rating  r ON (cbm.BusinessID=r.BusinessID)
GROUP BY r.BusinessID
ORDER BY bcount DESC
于 2013-08-29T10:14:44.080 回答