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当我尝试选择功能时

SELECT myDatabase.myFunction('');

我收到错误

ERROR 1142 (42000): SELECT command denied to user 'myUser'@'localhost' for table 'myTable'

虽然用户拥有所有权限

mysql> show grants for myUser;
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| Grants for myUser@%                                                                                                                                                            |
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| GRANT USAGE ON *.* TO 'myUser'@'%' IDENTIFIED BY PASSWORD ''                                                                                                                   |
| GRANT SELECT, INSERT, UPDATE, DELETE, CREATE, DROP, INDEX, ALTER, LOCK TABLES, EXECUTE, CREATE VIEW, SHOW VIEW, CREATE ROUTINE, ALTER ROUTINE ON `myDatabase`.* TO 'myUser'@'%'|
+--------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+

我也可以直接访问 myTable 没有任何问题。

任何帮助将不胜感激。

PS所有函数，表，数据库，用户名都可以，以防我在这篇文章中拼错了一些东西。

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1 回答 1

1

尝试 GRANT ALL；可能缺少 FUNCTION 权限

于 2013-08-29T12:38:22.843 回答