sql - 带有 group by 和 having 子句的 SQL 连接没有产生预期的结果

Question

我们有这四个表：

Store (
    row bigint,
    id uniqueidentifier,
    name varchar
)

Products (
    row bigint,
    id uniqueidentifier,
    storeID uniqueidentifier,
    productname varchar
)

Customer (
    row bigint,
    id uniqueidentifier,
    storeID uniqueidentifier,
    fName,
    lName,
    email
)

orders (
    row bigint,
    id uniqueidentifier,
    store_ID uniqueidentifier,
    cust_id uniqueidentifier,
    prod_id uniqueidentifier,
    date datetime
)

我们正在设计一个查询，它将查找从特定商店有 110 到 250 个订单的所有客户？

我们正在尝试列出客户名称、商店名称以及来自特定商店的该客户的订单数量。

我们尝试过的查询是：

select c.firstname + ' '+c.LastName, c.EmailAddress, s.name,  COUNT(o.id) from Orders o 
    inner join store s on s.ID=o.store_ID 
            inner join Customers c on c.ID=o.cust_ID 
    group by (c.firstname + ' '+c.LastName+cast(o.cust_ID as varchar(max) ))
    having count(o.id) >110 and count(o.id)<250

但是我们从上面的 join 语句中得到了错误。知道我们做错了什么吗？

Answer 1

尝试通过以下方式简单地列出组中的非聚合列：

select
    c.firstname + ' ' + c.LastName,
    c.EmailAddress,
    s.name,
    count(o.id)
from Orders o
inner join store s on s.ID=o.store_ID
inner join Customers c on c.ID=o.cust_ID
group by c.firstname + ' ' + c.LastName,
    c.EmailAddress,
    s.name
having count(o.id) between 111 and 249

还要注意通过使用betweenforhaving条件进行的简化，尽管因为包含在内而对范围值进行了修改between。

Answer 2

问题是您没有按 select 语句中的所有列进行分组：

select c.firstname + ' '+c.LastName, c.EmailAddress, s.name,  COUNT(o.id) from Orders o 
    inner join store s on s.ID=o.store_ID 
            inner join Customers c on c.ID=o.cust_ID 
    group by c.firstname + ' '+c.LastName, c.EmailAddress, s.name
    having count(o.id) >110 and count(o.id)<250