我似乎无法使用 spring mvc 中注入的 entitymgr 将数据保存在数据库中。我见过多个类似的问题（例如EntityManager cannot use persist to save element to database），但似乎没有一个答案能解决我的问题。这是我的配置：
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/tx
http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/aop
http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd">
<!-- datasource -->
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
destroy-method="close"
p:driverClassName="${driver}"
p:url="${url}"
p:username="contact" p:password="contact" />
<context:property-placeholder location="classpath:jdbc.properties" />
<bean id="entityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
p:dataSource-ref="dataSource"
p:packagesToScan="com.rd.web"> <!-- scans for entities (model) -->
<property name="persistenceProvider">
<bean class="org.hibernate.ejb.HibernatePersistence" />
</property>
<property name="jpaProperties">
<props>
<prop key="hibernate.dialect">
org.hibernate.dialect.MySQL5Dialect
</prop>
<prop key="hibernate.show_sql">true</prop>
</props>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"
p:entityManagerFactory-ref="entityManagerFactory" />
<tx:annotation-driven transaction-manager="transactionManager"/>
<context:component-scan base-package="com.rd.web" />
<bean id="contactService" class="com.rd.web.service.ContactServiceImpl"/>
</beans>
我有以下代码（在网络控制器中，但目前已移至服务进行测试）：
TEST_CASE1（使用弹簧事务）：
@Transactional
public Contact setContact(Contact c){
if(c.getId() == null){
getEMgr().persist(c);
}else{
getEMgr().merge(c);
}
return c;
}
==> 没有错误，只是没有插入实体，日志中也没有插入语句。
TEST_CASE2（使用弹簧事务）：
@Transactional
public Contact setContact(Contact c){
if(c.getId() == null){
getEMgr().persist(c);
}else{
getEMgr().merge(c);
}
getEMgr().flush();
return c;
}
==> 我得到的异常：没有正在进行的交易
测试案例3：
public Contact setContact(Contact c){
getEMgr().getTransaction().begin();
try{
if(c.getId() == null){
getEMgr().persist(c);
}else{
getEMgr().merge(c);
}
getEMgr().flush();
getEMgr().getTransaction().commit();
return c;
}catch(Throwable t){
getEMgr().getTransaction().setRollbackOnly();
}
return null;
}
==> 抛出错误：java.lang.IllegalStateException：不允许在共享 EntityManager 上创建事务 - 改用 Spring 事务或 EJB CMT
它不应该是 Spring AOP 问题，因为该操作是公共的，并且是从另一个组件（服务被注入的组件）调用的。appcontext 还将事务定义为注释驱动程序。我真的不明白为什么我的交易没有开始。
当我使用相同的 applicationcontext.xml 并触发一个加载联系人服务并创建联系人的测试类时，联系人被正确保存。
我还在 web.xml 中添加了以下过滤器，但无济于事：
<filter>
<filter-name>SpringOpenEntityManagerInViewFilter</filter-name>
<filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>SpringOpenEntityManagerInViewFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
任何提示将不胜感激。干杯。
添加了一些额外的信息：
@Muel，正在使用持久性上下文注入 entitymgr：
@Transactional
@Service("contactService") 公共类 ContactServiceImpl 实现 IContactService {
// @Autowired // 私有 IEntityMgrProvider eMgrPovider;
@PersistenceContext EntityManager eMgr;
@Transactional
public Contact getContactByID(long id) {
return getEMgr().find(Contact.class, id);
}
@Transactional
public List<Contact> getAllContacts() {
TypedQuery<Contact> qry = getEMgr().createNamedQuery("findAll", Contact.class);
return qry.getResultList();
}
@Transactional
public Contact setContact(Contact c){
if(c.getId() == null){
getEMgr().persist(c);
// getEMgr().flush();
}else{
getEMgr().merge(c);
}
return c;
}
@Transactional(readOnly=true)
public void deleteContact(long id){
getEMgr().remove(getEMgr().find(Contact.class, id));
}
private EntityManager getEMgr(){
// return eMgrPovider.getEMgr();
return eMgr;
}
public static void main(String[] args) {
ClassPathXmlApplicationContext ctx = new ClassPathXmlApplicationContext("appctx.xml");
IContactService contactService = ctx.getBean("contactService", IContactService.class);
Contact c= new Contact();
c.setBirthDate(new Date());
c.setFirstName("P1");
c.setLastName("P2");
ContactTelDetail tel = new ContactTelDetail();
tel.setContact(c);
tel.setTelNumber("056776650");
tel.setTelType("landline");
c = contactService.setContact(c);
System.out.println(c.getId());
}
}
我意识到这个 getEmgr() 方法不是必需的，但最初 eMgr 来自其他地方（它也被注入，但暂时不要介意）顺便说一句，当我运行 main 方法时，我实际上可以插入联系人......
@user2264997 这是我的 servlet 上下文：
<?xml version="1.0" encoding="UTF-8"?>
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>
<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<!-- Processes application requests -->
<servlet>
<servlet-name>appServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>appServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
<filter>
<filter-name>encodingFilter</filter-name>
<filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
<init-param>
<param-name>encoding</param-name>
<param-value>UTF-8</param-value>
</init-param>
<init-param>
<param-name>forceEncoding</param-name>
<param-value>true</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>encodingFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<filter>
<filter-name>SpringOpenEntityManagerInViewFilter</filter-name>
<filter-class>org.springframework.orm.jpa.support.OpenEntityManagerInViewFilter</filter-class>
</filter>
<filter-mapping>
<filter-name>SpringOpenEntityManagerInViewFilter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
</web-app>
我只添加了最后两个过滤器进行测试。我不认为它应该是必需的（似乎最后一个过滤器仅用于支持延迟加载或其他东西，但无论如何都尝试过......）
@马丁弗雷
我会看看你可能会做些什么。
@mdeinum.wordpress.com
使用@autowired 将服务注入到 web 控制器中。服务实现和 web.xml 见上文。调度程序 servlet 的配置文件（尽管它似乎没有相关信息，但也许这可能是问题；））：
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/mvc"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd">
<!-- DispatcherServlet Context: defines this servlet's request-processing infrastructure -->
<!-- use this dispatcher servlet for root -->
<!-- <default-servlet-handler/> -->
<resources location="/, classpath:/META-INF/web-resources/" mapping="/resources/**"/>
<interceptors>
<beans:bean class="org.springframework.web.servlet.theme.ThemeChangeInterceptor"/>
<beans:bean class="org.springframework.web.servlet.i18n.LocaleChangeInterceptor"
p:paramName="lang"/>
</interceptors>
<beans:bean
class="org.springframework.ui.context.support.ResourceBundleThemeSource"
id="themeSource" />
<beans:bean class="org.springframework.web.servlet.theme.CookieThemeResolver"
id="themeResolver" p:cookieName="theme" p:defaultThemeName="standard" />
<beans:bean
class="org.springframework.context.support.ReloadableResourceBundleMessageSource"
id="messageSource" p:basenames="WEB-INF/i18n/messages,WEB-INF/i18n/application"
p:fallbackToSystemLocale="false" />
<beans:bean class="org.springframework.web.servlet.i18n.CookieLocaleResolver"
id="localeResolver" p:cookieName="locale"/>
<!-- Enables the Spring MVC @Controller programming model -->
<annotation-driven />
<!-- Handles HTTP GET requests for /resources/** by efficiently serving up static resources in the ${webappRoot}/resources directory -->
<!-- <resources location="/resources/" mapping="/resources/**" /> -->
<!-- Resolves views selected for rendering by @Controllers to .jsp resources in the /WEB-INF/views directory -->
<!-- now using tiles in stead ==> different view resolver -->
<!-- <beans:bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> -->
<!-- <beans:property name="prefix" value="/WEB-INF/views/" /> -->
<!-- <beans:property name="suffix" value=".jsp" /> -->
<!-- </beans:bean> -->
<context:component-scan base-package="com.rd.web" />
<!-- Add the following beans -->
<!-- Tiles Configuration -->
<beans:bean class="org.springframework.web.servlet.view.UrlBasedViewResolver"
id="tilesViewResolver">
<beans:property name="viewClass"
value="org.springframework.web.servlet.view.tiles2.TilesView" />
</beans:bean>
<beans:bean
class="org.springframework.web.servlet.view.tiles2.TilesConfigurer"
id="tilesConfigurer">
<beans:property name="definitions">
<beans:list>
<beans:value>/WEB-INF/layouts/layouts.xml</beans:value>
<!-- Scan views directory for Tiles configurations -->
<beans:value>/WEB-INF/views/**/views.xml</beans:value>
</beans:list>
</beans:property>
</beans:bean>
</beans:beans>
我将尝试配置休眠适配器并让您知道它是如何进行的...
干杯