我很快整理了一些脚本。我假设您的输入文件具有固定格式,从某种意义上说,值的长度不会在行之间发生变化。这样可以更容易地从线条中提取您需要的东西,例如“粗体部分”。如果它们不固定,则提取可能需要正则表达式,但脚本的一般结构不应改变。
disp(' ');
fname = 'data.txt';
% desired output line format
desiredlineTemplate = '1 255 %s %s\n';
boldPart = '';
fid = fopen(fname);
% get first line
tline = fgets(fid);
if numel(tline) > 36
% check if first line in a file is a PS line
% based on its length.
% lines with PS are much longer than the lines without PS
% so we can use this information
% extract the "bold part"
boldPart = tline(39:end-4);
% remove commas
boldPart = strrep(boldPart,',','');
end
while ischar(tline)
% disp(tline);
if numel(tline) == 1,
% enmpty lines have length of 1. At least
% when I tried this. If this is not the case for your
% text file, u can ignor this bit.
tline = fgets(fid);
continue;
end
% lines with PS are much longer than the lines without PS
% so we can use this information
if numel(tline) > 36
% this is a line with PS
% so extract "bold part"
boldPart = tline(39:end-4);
% remove comma
boldPart = strrep(boldPart,',','');
else
% now we are in a line without PS. Thus need to reformat this line
% and add "bold part" extracted earlier.
% extract the first number in a line
% again based on ints length
firstNumber = tline(1:17);
% CONSTRUCT THE DISIRED LINE OUTPUT
desiredLine = sprintf(desiredlineTemplate, boldPart, firstNumber);
disp(desiredLine);
end
tline = fgets(fid);
end
fclose(fid);
输出是:
>>
1 255 40.497522 -74.434818 0.026000 1377303313.320448
1 255 40.497522 -74.434818 0.026000 1377303313.369429
1 255 40.497522 -74.434818 0.026000 1377303313.419430
1 255 40.497522 -74.434818 0.026000 1377303313.468416
1 255 40.497521 -74.434819 0.010000 1377303313.715420
1 255 40.497521 -74.434819 0.010000 1377303313.814361