0

下面是我的代码中的数组格式的两个示例，完整代码和数组内容。

阵列 1

Array
(
[version] => 1.0
[injuries] => Array
(
[timestamp] => 1377702112
[week] => 1
[injury] => Array
(
[0] => Array
(
[status] => Questionable
[id] => 10009
[details] => Shoulder

)

[1] => Array
(
[status] => Questionable
[id] => 10012
[details] => Ankle

)

阵列 2

Array
(
[version] => 1.0
[players] => Array
(
[timestamp] => 1377676937
[player] => Array
(
[0] => Array
(
[position] => TMDL
[name] => Bills, Buffalo
[id] => 0251
[team] => BUF
)

[1] => Array
(
[position] => TMDL
[name] => Colts, Indianapolis
[id] => 10009
[team] => IND
)

我需要做的是对两个数组进行排序并找到 ID 键的匹配值。然后我需要将两个数组的值合并到一个数组中，这样我就可以在屏幕上打印出来。提供了两个 API，一个用于带有球员 [id] 键的伤病报告，另一个用于带有 [id] 键的球员信息。这是我在这个问题上的进展：

<?php

       function injuries_report() {         

       //Get json files

         $injuryData = file_get_contents('http://football.myfa...=1&callback=');
         $playerData = file_get_contents('http://football.myfa...L=&W=&JSON=1');

       //format json data into an array

          $obj1 = json_decode($injuryData, true);
         $obj2 = json_decode($playerData, true);



         //return print_r($obj1);   //print obj1 to see output

         return print_r($obj2);     //print obj2 to see output

       }

      ?> 

       <!--get injuries report -->

      <pre><?php injuries_report(); ?></pre>

这是工作代码，感谢克里斯:)

$injuryData = file_get_contents('http://football.myfantasyleague.com/2013/export?TYPE=injuries&L=&W=&JSON=1&callback=');
    $array1 = json_decode($injuryData, true);
    $playerData = file_get_contents('http://football.myfantasyleague.com/2013/export?TYPE=players&L=&W=&JSON=1');
    $array2 = json_decode($playerData, true);

    function map($x) {
       global $array1;
       if(isset($x['id'])) {
          $id = $x['id'];
          $valid = array_filter($array1['injuries']['injury'], create_function('$injury', 'return $injury["id"] == "' . $id .'";'));
          if(count($valid) > 0) {
             $x = array_merge($x, array_shift($valid));
          }
           }
           return $x;
        }
        $output = array_map('map', $array2['players']['player']);
        echo "<pre>";
        print_r($output);
        echo "</pre>";
4

1 回答 1

1

好的，我假设你想给球员增加伤害。输出将是球员名单，加上伤害（他们适用的地方）

$output = array_map(function($x) use ($array1) {
   $id = $x['id'];
   $valid = array_filter($array1['injuries']['injury'], function($injury) use ($id) {
      return $injury['id'] == $id;
   });
   if(count($valid) > 0) {
      $x = array_merge($x, $valid[0]);
   }
   return $x;
}, $array2['players']['player']);

print_r($output);

输出是这样的：

Array
(
    [0] => Array
        (
            [position] => TMDL
            [name] => Bills, Buffalo
            [id] => 0251
            [team] => BUF
        )

    [1] => Array
        (
            [position] => TMDL
            [name] => Colts, Indianapolis
            [id] => 10009
            [team] => IND
            [status] => Questionable
            [details] => Shoulder
        )
)

php 5.2

编辑最新的工作版本：

哦，您使用的是 php 5.2。这是一个 php 5.2 版本，但它不如之前的代码漂亮：

$injuryData = file_get_contents('http://football.myfantasyleague.com/2013/export?TYPE=injuries&L=&W=&JSON=1&callback=');
$array1 = json_decode($injuryData, true);
$playerData = file_get_contents('http://football.myfantasyleague.com/2013/export?TYPE=players&L=&W=&JSON=1');
$array2 = json_decode($playerData, true);

function map($x) {
   global $array1;
   if(isset($x['id'])) {
      $id = $x['id'];
      $valid = array_filter($array1['injuries']['injury'], create_function('$injury', 'return $injury["id"] == "' . $id .'";'));
      if(count($valid) > 0) {
         $x = array_merge($x, array_shift($valid));
      }
   }
   return $x;
}
$output = array_map('map', $array2['players']['player']);
print_r($output);

这里$array1是全球性的。在这里检查：http: //pastebin.com/N3RqtfzN

于 2013-08-28T18:42:27.790 回答