3

我有一个注册表。在这里，我可以通过我的自定义是唯一的回调函数检查重复的电子邮件（不要尝试使用 is_unique）。但它不返回任何东西。这是我的代码。

控制器 -

public function add_member () {

    $this->load->library('form_validation');

    $post_email = $this->input->post('email_id');
    $this->form_validation->set_rules('email_id', 'Email ID/ Username', 'required|trim|xss_clean|valid_email|callback_check_duplicate_email[' . $post_email . ']');
    $this->form_validation->set_rules('password', 'Your password', 'required|min_length[5]|max_length[12]|matches[confirm_password');
    $this->form_validation->set_rules('confirm_password', 'Password Confirmation', 'required');

    $this->form_validation->set_message('check_duplicate_email', 'This email is already exist. Please write a new email.');

    if ($this->form_validation->run() == FALSE) {
        // validation failed then do that

        $this->load->view('member/reg_form');

    } else {

        $data['email_id'] = $post_email;
        $data['password'] = MD5($this->input->post('password'));

        $insert = $this->Model_member->insert_data_to_db($data);

        if ($insert) {
            $success = "Wao ! You are successfully added to our community.";
            $this->session->set_flashdata('message_success', $success);
            $this->load->view('member/success_page');
        } else {
            $error = "Hey this email is already exists in our community.";
            $this->session->set_flashdata('message_error', $error);
            $this->load->view('member/reg_form');
        }
    }

}

// My callback function
public function check_duplicate_email($post_email) {

    return $this->Model_member->checkDuplicateEmail($post_email);

}

模型 -

 //for checking email existance
 public function checkDuplicateEmail($post_email) {

    $this->db->where('email_id', $email_id);

    $query = $this->db->get('my_registration_table');

    $count_row = $query->num_rows();

    if ($count_row > 0) {
        return TRUE;
    } else {
        return FALSE;
    }
}

// insert data to DB
public function insert_data_to_db($data) {
    return $this->db->insert('my_registration_table', $data);
}

当我尝试使用已经存在的电子邮件提交表单时。此功能不会阻止我，也不会显示验证错误消息。有人会在这里看看有什么问题吗？等待您的帮助。

4

4 回答 4

8

您的问题出在模型功能中。看下面的模型函数。

public function checkDuplicateEmail($post_email) {

    $this->db->where('email_id', $email_id);

    $query = $this->db->get('my_registration_table');

    $count_row = $query->num_rows();

    if ($count_row > 0) {
      //if count row return any row; that means you have already this email address in the database. so you must set false in this sense.
        return FALSE; // here I change TRUE to false.
     } else {
      // doesn't return any row means database doesn't have this email
        return TRUE; // And here false to TRUE
     }
}

试试这个。希望有效。

于 2013-08-28T16:16:30.433 回答
1 
Call the right method in your model, as you defined in your controller.And your variable name should be same as argument passed in your function.I think it works.
Model:

public function insert_data_to_db($post_email) {

    $this->db->where('email_id', $post_email);

    $query = $this->db->get('my_registration_table');

    $count_row = $query->num_rows();

    if ($count_row > 0) {
        return TRUE;
    } else {
        return FALSE;
    }
}
于 2013-08-28T16:28:00.520 回答
1

您标记为正确的答案是正确的，但是您最终会遇到逻辑错误。

您传入了保存在 $post_email 中的电子邮件 ID，但 codeigniter 允许您传入正在修剪、清理等的变量。

因此，由于您要按原样保存帖子数据的副本，如果有空格或其他不应该修剪的东西，但修剪后的版本是匹配的，它将不匹配。

换句话说：“me@my.com”可能不匹配“me@my.com”通过您的验证，然后存储“me@my.com”的 2 个副本。

$this->form_validation->set_rules('email_id', 'Email ID/ Username', 'required|trim|xss_clean|valid_email|callback_check_duplicate_email[email_id]');
于 2015-08-24T21:15:11.710 回答
0

如果我没记错的话，该功能应该在控制器中，而不是在模型中。

于 2013-08-28T16:10:54.813 回答