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我在用户控件中有一个文本框。我动态地创建了这个用户控件并加载到占位符中。

但是当我尝试为文本框赋值时,我提出了下一个错误:

Object reference not set to an instance of an object

这是用户控件:

<%@ Control Language="C#" AutoEventWireup="true" CodeBehind="IVT_FormClient.ascx.cs" Inherits="Evi.Sc.Web.Evi.IVT.Sublayouts.IVT_FormClient" %>
<asp:Panel ID="pnlContainer" runat="server">        
    <asp:TextBox ID="txtClientNumber" runat="server"></asp:TextBox>
</asp:Panel>

访问修饰符是(在用户控件中):

public string TxtFirstName
{
    get { return txtFirstName.Text; }
    set { txtFirstName.Text = value; }
}

在网络表单中,我有控件参考:

<%@ Reference Control="~/Evi/IVT/Sublayouts/IVT_FormClient.ascx"   %>

在用户控件背后的代码是:

    public partial class frm_VerifyIdentity : System.Web.UI.Page
    {
        IVT_FormClient ivtFormClient = new IVT_FormClient();

        protected void Page_Load(object sender, EventArgs e)
        {
            if (!IsPostBack)
            {
            IVT_FormClient ivtFormClient = (IVT_FormClient)LoadControl("~/Evi/IVT/Sublayouts/IVT_FormClient.ascx");

                Client UserClient = new Client();

                UserClient = Load_ClientVerification(Server.HtmlEncode(Request.QueryString["ID"]).Trim());

                if (UserClient != null)
                {
                    ivtFormClient.TxtFirstName = UserClient.FirstName;
                    plhFormClient.Controls.Add(ivtFormClient);
                }

            }
        }
 }

发生的错误是这行代码:

                ivtFormClient.TxtFirstName = UserClient.FirstName;
4

1 回答 1

0

不要创建UserControlvia 构造函数的实例,而是使用LoadControl您已经在Page_Load. 但是,您只是这样做if(!IsPostBack)。因此,控件通过构造函数在下一次回发时实例化。

此外,您必须在每次回发时重新创建动态控件。我建议将 UserControl delaratively 添加到页面中。您可以相应地隐藏/显示它。否则,您需要始终创建/添加它,最好Page_InitPage_Load.

所以这不是最佳实践(只需将其添加到页面中),但应该可以按需要工作:

IVT_FormClient ivtFormClient = null;

protected void Page_Init(object sender, EventArgs e)
{
    ivtFormClient =(IVT_FormClient)LoadControl("~/Evi/IVT/Sublayouts/IVT_FormClient.ascx");
    Client UserClient = new Client();
    UserClient = Load_ClientVerification(Server.HtmlEncode(Request.QueryString["ID"]).Trim());

    if (UserClient != null)
    {
        ivtFormClient.TxtFirstName = UserClient.FirstName;
        plhFormClient.Controls.Add(ivtFormClient);
    }
}
于 2013-08-28T13:03:23.853 回答