0

我收到了最新的推文，结果如下所示：

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    "created_at": "Wed Aug 28 11:50:22 +0000 2013",
    "id": 372687598952919040,
    "id_str": "372687598952919040",
    "text": "\"I fear we'll get ourselves involved in another endless conflict\" - Ukip's @Nigel_Farage on UK's #Syria decision http:\/\/t.co\/3iMlO9BHks",
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        "description": "News, features and analysis from BBC News (UK edition). For world edition, follow @BBCWorld. For breaking news, follow @BBCBreaking. Latest sport news @BBCSport",
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        "created_at": "Mon Jan 08 08:05:57 +0000 2007",
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            "text": "Syria",
            "indices": [97, 103]
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            "url": "http:\/\/t.co\/3iMlO9BHks",
            "expanded_url": "http:\/\/bbc.in\/13YTz5f",
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        "user_mentions": [{
            "screen_name": "Nigel_Farage",
            "name": "Nigel Farage",
            "id": 19017675,
            "id_str": "19017675",
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    },
    "favorited": false,
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}, {
    "created_at": "Wed Aug 28 11:27:11 +0000 2013",
    "id": 372681763640061952,
    "id_str": "372681763640061952",
    "text": "International agreement, legal basis, support in country - @HarrietHarman on criteria needed to support Syria action http:\/\/t.co\/I5fWeyt9gl",
    "source": "<a href=\"http:\/\/www.bbc.co.uk\/news\/\" rel=\"nofollow\">BBC News<\/a>",
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        "screen_name": "BBCNews",
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        "symbols": [],
        "urls": [{
            "url": "http:\/\/t.co\/I5fWeyt9gl",
            "expanded_url": "http:\/\/bbc.in\/13YQD8O",
            "display_url": "bbc.in\/13YQD8O",
            "indices": [117, 139]
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        "user_mentions": [{
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            "name": "Harriet Harman",
            "id": 19977759,
            "id_str": "19977759",
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}]

我该如何使用它，以便我可以从数组中挑选推文，例如。$tweets[2];我试过 json_decode 但没有运气。

4

2 回答 2

1

您可以尝试将第二个参数传递给 json_decode，它将所有 json 数据转储为关联数组 链接

于 2013-08-28T12:20:09.490 回答
0

如果您尝试将 JSON 输出存储在字符串中，则会由于其中未转义的单引号而失败。

例如，您在 JSON 输出中有以下文本：

"text": "\"I fear we'll get ourselves involved in another endless conflict\" 
            //------^

因此，如果您尝试将 JSON 分配给字符串，它将失败并由于其中的单引号而产生解析错误。因为您的 JSON 包含双引号，所以您也不能使用它。

要告诉 PHP 忽略引号并将其解释为字符串，可以使用heredoc语法，如下所示：

$string = <<<JSON
... json ...
JSON;

$json = json_decode($string);
echo $json[0]->text."\n"; 
echo $json[1]->text."\n";

注意：如果你想获得一个关联数组，你可以传递json_decode()as的第二个参数TRUE。

工作演示！

于 2013-08-28T12:17:12.947 回答