我想在下面显示这张表
September 2013
- 14/09/2013 | 14:30 | Football | League | Paris - Berlin
- 14/09/2013 | 19:30 | Volley | Cup | Paris - Barcelona
- 25/09/2013 | 12:00 | Football | Amical | Paris - Bordeaux
October 2013
- 5/10/2013 | 15: 00 | Cup | Paris - Londres
这是我的代码
$dateQuery = mysql_query("SELECT matches.id, date_debut, date_fin, matches.score,sports.title AS 运动, clubs1.title AS recevant, clubs2.title AS 访客, Competitions.title AS 比赛,matches.description, sexes.title作为性
FROM 匹配项
在 sexes.id =matches.sexe_id 上的 INNER JOIN 性别
在 sports.id = matches.sport_id 上的内部加入运动
INNER JOIN clubs AS clubs1 ON clubs1.id = matches.recevant_id
INNER JOIN clubs AS clubs2 ON clubs2.id = matches.visiteur_id
INNER JOIN 比赛 ON Competitions.id = matches.competition_id
WHERE CURRENT_DATE()<=date_debut
ORDER BY date_debut ASC") 或 die(mysql_error());
while($row=mysql_fetch_assoc($dateQuery)){
print '<b>'.$tIndexed[$row['date_debut'] ][ $row['sport'] ][]=date("d-m-Y",strtotime($row['date_debut'])).'</b><br />';
foreach($tIndexed as $sDate => $tIndexedDate){
foreach($tIndexedDate as $sEvenement => $tIndexedEvenement){
foreach($tIndexedEvenement as $sTexte){
$sTexte = $row['recevant'].'-'.$row['visiteur'];
print date("H:i",strtotime($row['date_debut'])).' | ' .$row['sport'].' | '.$row['competition'].' | '.$sTexte.' <br />';
}
}
}
}
结果显示错误
14-09-2013
14:30 | Football | Championnat de France | IOS ORLEANS-CSSM PARIS
14-09-2013
19:30 | Football | Championnat de France | CSSM PARIS-ASLS NANCY
19:30 | Football | Championnat de France | CSSM PARIS-ASLS NANCY
21-09-2013
15:00 | Football | Championnat de France | CSS RENNES-CSSM PARIS
15:00 | Football | Championnat de France | CSS RENNES-CSSM PARIS
15:00 | Football | Championnat de France | CSS RENNES-CSSM PARIS
28-09-2013
19:30 | Football | Championnat de France | CSSM PARIS-CSS RENNES
19:30 | Football | Championnat de France | CSSM PARIS-CSS RENNES
19:30 | Football | Championnat de France | CSSM PARIS-CSS RENNES
19:30 | Football | Championnat de France | CSSM PARIS-CSS RENNES
我希望你能帮助我解决这个问题。
谢谢