我正在开发一个应用程序，我必须在其中获取当前位置（纬度/经度）附近的所有位置名称，并且所有位置都应在 1000 米半径范围内。
现在我为此点击 API URL：
我每次都得到回应：
{
"debug_info" : [],
"html_attributions" : [],
"results" : [],
"status" : "REQUEST_DENIED"
}
我的代码：
private String makeUrl(double latitude, double longitude,String place)
{
StringBuilder urlString = new StringBuilder("https://maps.googleapis.com/maps/api/place /search/json?");
if (place.equals("")) {
urlString.append("&location=");
urlString.append(Double.toString(latitude));
urlString.append(",");
urlString.append(Double.toString(longitude));
urlString.append("&radius=1000");
//urlString.append("&types="+place);
urlString.append("&sensor=false&key=" + API_KEY);
} else {
urlString.append("&location=");
urlString.append(Double.toString(latitude));
urlString.append(",");
urlString.append(Double.toString(longitude));
urlString.append("&radius=1000");
//urlString.append("&types="+place);
urlString.append("&sensor=false&key=" + API_KEY);
}
return urlString.toString();
}
private String getUrlContents(String theUrl)
{
StringBuilder content = new StringBuilder();
try {
URL url = new URL(theUrl);
URLConnection urlConnection = url.openConnection();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream()), 8);
String line;
while ((line = bufferedReader.readLine()) != null)
{
content.append(line + "\n");
}
bufferedReader.close();
}
catch (Exception e)
{
e.printStackTrace();
}
return content.toString();
}