我有以下查询和方法
private static final String FIND = "SELECT DISTINCT domain FROM Domain domain LEFT OUTER JOIN FETCH domain.operators LEFT OUTER JOIN FETCH domain.networkCodes WHERE domain.domainId = :domainId";
@Override
public Domain find(Long domainId) {
Query query = getCurrentSession().createQuery(FIND);
query.setLong("domainId", domainId);
return (Domain) query.uniqueResult();
}
与Domain
作为
@Entity
@Table
public class Domain {
@Id
@GenericGenerator(name = "generator", strategy = "increment")
@GeneratedValue(generator = "generator")
@Column(name = "domain_id")
private Long domainId;
@Column(nullable = false, unique = true)
@NotNull
private String name;
@Column(nullable = false)
@NotNull
@Enumerated(EnumType.STRING)
private DomainType type;
@OneToMany(cascade = {
CascadeType.PERSIST,
CascadeType.MERGE
}, fetch = FetchType.EAGER)
@JoinTable(joinColumns = {
@JoinColumn(name = "domain_id")
}, inverseJoinColumns = {
@JoinColumn(name = "code")
})
@NotEmpty
@Valid // needed to recur because we specify network codes when creating the domain
private Set<NetworkCode> networkCodes = new HashSet<>();
@ManyToMany(fetch = FetchType.EAGER)
@JoinTable(joinColumns = {
@JoinColumn(name = "parent", referencedColumnName = "domain_id")
}, inverseJoinColumns = {
@JoinColumn(name = "child", referencedColumnName = "domain_id")
})
private Set<Domain> operators = new HashSet<>();
// more
}
我希望这个单个查询能够获取Set<NetworkCode>
and Set<Domain
> 关系,但事实并非如此。假设Domain
I 查询有两个运算符,Hibernate 将执行 1 + 2 * 2 = 5 次查询
Hibernate: select distinct domain0_.domain_id as domain1_1_0_, domain2_.domain_id as domain1_1_1_, networkcod4_.code as code2_2_, domain0_.name as name1_0_, domain0_.type as type1_0_, domain2_.name as name1_1_, domain2_.type as type1_1_, operators1_.parent as parent1_0__, operators1_.child as child4_0__, networkcod3_.domain_id as domain1_1_1__, networkcod3_.code as code5_1__ from domain domain0_ left outer join domain_operators operators1_ on domain0_.domain_id=operators1_.parent left outer join domain domain2_ on operators1_.child=domain2_.domain_id inner join domain_network_codes networkcod3_ on domain0_.domain_id=networkcod3_.domain_id inner join network_code networkcod4_ on networkcod3_.code=networkcod4_.code where domain0_.domain_id=?
Hibernate: select operators0_.parent as parent1_1_, operators0_.child as child4_1_, domain1_.domain_id as domain1_1_0_, domain1_.name as name1_0_, domain1_.type as type1_0_ from domain_operators operators0_ inner join domain domain1_ on operators0_.child=domain1_.domain_id where operators0_.parent=?
Hibernate: select networkcod0_.domain_id as domain1_1_1_, networkcod0_.code as code5_1_, networkcod1_.code as code2_0_ from domain_network_codes networkcod0_ inner join network_code networkcod1_ on networkcod0_.code=networkcod1_.code where networkcod0_.domain_id=?
Hibernate: select operators0_.parent as parent1_1_, operators0_.child as child4_1_, domain1_.domain_id as domain1_1_0_, domain1_.name as name1_0_, domain1_.type as type1_0_ from domain_operators operators0_ inner join domain domain1_ on operators0_.child=domain1_.domain_id where operators0_.parent=?
Hibernate: select networkcod0_.domain_id as domain1_1_1_, networkcod0_.code as code5_1_, networkcod1_.code as code2_0_ from domain_network_codes networkcod0_ inner join network_code networkcod1_ on networkcod0_.code=networkcod1_.code where networkcod0_.domain_id=?
我猜这是因为我加入了运营商Domain
元素,但他们必须加入自己。
是否有一个我可以执行的 HQL 查询可以两者兼得?