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我有这样实现的对话框片段

public class SessionExpiredFragment extends DialogFragment {

    public interface SessionExpiredFragmentListener {
        public void onCancelLoginProcessPressed(DialogFragment dialog);

        // validValues = true if fields are not empty and email is a valid
        // email,
        // else validValues = false;
        public void onOKLoginProcessPressed(DialogFragment dialog,
                boolean validValues);
    }

    SessionExpiredFragmentListener mListener;

    @Override
    public void onAttach(Activity activity) {
        super.onAttach(activity);
        try {
            mListener = (SessionExpiredFragmentListener) activity;
        } catch (ClassCastException e) {
            throw new ClassCastException(activity.toString()
                    + " must implement SessionExpiredFragmentListener");
        }
    }

    // UI references
    private EditText mEmailView;
    private EditText mPasswordView;
    private View mLoginFormView;
    private View mLoginStatusView;

    @Override
    public Dialog onCreateDialog(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        AlertDialog.Builder builder = new AlertDialog.Builder(getActivity());
        LayoutInflater inflater = getActivity().getLayoutInflater();

        View view = inflater.inflate(R.layout.login_fragment_layout, null);
        /*
         * Get edit texts references
         */
        mEmailView = (EditText) view.findViewById(R.id.email);
        mPasswordView = (EditText) view.findViewById(R.id.password);
        mLoginFormView = view.findViewById(R.id.login_form);
        mLoginStatusView = view.findViewById(R.id.login_status);

        /*
         * Set builder values
         */
        builder.setMessage(R.string.session_expired_title)
                .setView(view)
                .setPositiveButton(R.string.action_ok,
                        new DialogInterface.OnClickListener() {

                            @Override
                            public void onClick(DialogInterface dialog,
                                    int which) {
                                boolean validValues = true;
                                String email = mEmailView.getText().toString();
                                String password = mPasswordView.getText()
                                        .toString();
                                if (TextUtils.isEmpty(email)
                                        || TextUtils.isEmpty(password))
                                    validValues = false;
                                if (!isValidEmail(email))
                                    validValues = false;

                                mListener.onOKLoginProcessPressed(
                                        SessionExpiredFragment.this,
                                        validValues);
                            }
                        })
                .setNegativeButton(R.string.action_cancel,
                        new DialogInterface.OnClickListener() {

                            @Override
                            public void onClick(DialogInterface dialog,
                                    int which) {
                                mListener
                                        .onCancelLoginProcessPressed(SessionExpiredFragment.this);

                            }
                        });
        return builder.create();
    }

它有正面和负面按钮。我需要做的是在按下正按钮时隐藏它们。我使用了这个监听器,所以我可以在我的活动中收听,但这对我也没有帮助。如何(以及在​​何处添加该代码)隐藏按钮?谢谢您的帮助。

4

3 回答 3

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Button negativeButton = alert.getButton(AlertDialog.BUTTON_NEGATIVE);
buttonNo.setEnabled(false);
于 2013-08-27T13:08:45.820 回答
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然后您应该考虑创建自定义视图并通过代码管理按钮的可见性

于 2013-08-27T13:21:27.857 回答
0

只需覆盖 DialogFragment 中的 onStart() 并保留对按钮的引用。您可以稍后使用参考重新启用该按钮:

Button positiveButton;

@Override
public void onStart() {
    super.onStart();
    AlertDialog d = (AlertDialog) getDialog();
    if (d != null) {
        positiveButton = (Button)d.getButton(Dialog.BUTTON_POSITIVE);
        positiveButton.setEnabled(false);
    }

}
于 2014-05-05T20:42:02.063 回答