1

我对angularJs很陌生。

我正在尝试根据 url 参数检索对象。

例如我有以下代码：

var tripApp = angular.module('tripApp', ['ui.state', 'ui.bootstrap', 'restangular', 'tripApp.directives', 'restaurantServices'])
    tripApp.config(function($stateProvider, $urlRouterProvider, RestangularProvider){

      RestangularProvider.setBaseUrl('json');
      RestangularProvider.setRequestSuffix('.json');

      $urlRouterProvider.otherwise("/hotels")

      $stateProvider
        .state('hotels', {
            url: "/hotels/:id",
            templateUrl: "templates/hotels.html",
            controller: "HotelDetailController"
        })

我的控制器为：

tripApp.controller('HotelDetailController', function($scope, $timeout, Restangular) {


});

如果我的 json 文件是：我如何能够根据字段“url”检索记录：

{
    "hotels":
    [
        {
            "url":"bandos-island-resort",
            "name": "Bandos Island",
            "city": "Male",
            "country": "Maldives",
            "img": "http://www.barcelo.com/BarceloHotels/en_GB/Images/oviedo-barcelo-hotels-views.jpg21-29254.jpg",
            "price": 199,
            "offer": 50,
            "standard": [1, 2, 3, 4],
            "roomsleft": 4,
            "facilities": [
                {
                    "wifi": true,
                    "breakfast": false,
                    "spa": false,
                    "beachAccess": false,
                    "pool": false,
                    "airportShuttle": false,
                    "restaurant": false,
                    "bar": false,
                    "coffeeShop": false,
                    "noSmoking": false,
                    "petFriendly": false,
                    "jacuzzi": false,
                    "laundry": true,
                    "miniBar": false,
                    "parking": false,
                    "roomService": false,
                    "sauna": false,
                    "scubaDiving": false,
                    "snorkeling": false,
                    "waterSkiing": false,
                    "windSurfing": false,
                    "tennis": false,
                    "golf": false,
                    "weddingPlan": false
                }
            ] 
        },
        {
            "url":"bandos-island-resort",
            "name": "Club Faru",
            "img": "http://www.barcelo.com/BarceloHotels/en_GB/Images/oviedo-barcelo-hotels-views.jpg21-29254.jpg",
            "price": 299,
            "offer": 0,
            "standard": [1, 2, 3],
            "roomsleft": 4,
            "facilities": [
                {
                    "wifi": true,
                    "breakfast": false,
                    "spa": false,
                    "beachAccess": false,
                    "pool": false,
                    "airportShuttle": false,
                    "restaurant": false,
                    "bar": false,
                    "coffeeShop": false,
                    "noSmoking": false,
                    "petFriendly": false,
                    "jacuzzi": false,
                    "laundry": false,
                    "miniBar": false,
                    "parking": false,
                    "roomService": false,
                    "sauna": false,
                    "scubaDiving": false,
                    "snorkeling": false,
                    "waterSkiing": false,
                    "windSurfing": false,
                    "tennis": false,
                    "golf": false,
                    "weddingPlan": false
                }
            ]
        }
    ]
}

我能够检索整个文件并重复数据，但我想根据 url 字段过滤记录并在我的视图中使用它。任何帮助，将不胜感激。谢谢

4

1 回答 1

1

您正在寻找的是服务 $routeParams。从文件或 AJAX 请求中获取数据后，您可以使用 $routeParams.id 在您的路线中获取 :id。

这是一个非常简单的例子（来自小提琴）

<div ng-app="myApp">
    <div ng-view></div>
    <script type="text/ng-template" id="/page.html">
    My ID is: {{id}}
    </script>
</div>

应用程序.js

var app = angular.module('myApp', [])
.config(function($routeProvider) {
    $routeProvider
    .when('/page/:id', {templateUrl: '/page.html', controller: 'PageController'})
    .otherwise({redirectTo:'/page/50'});
}).controller('PageController', function($scope, $routeParams) {
    $scope.id = parseInt($routeParams.id);
});
于 2013-08-27T12:32:54.687 回答