unix - 查找文件中以修复字符串开头的所有单词？

Question

如何在我的 csv 文件中找到以 $ 开头的所有单词

我的文件是这样的：

Test1,$Var1,$varCab1,$Vargab1,Comment1
Test2,$Var2,$varCab2,$Vargab2,Comment2
Test3,$Var3,$varCab3,$Vargab3,Comment3

作为我想要的输出

$Var1
$varCab1
$Vargab1
$Var2
$varCab2
$Vargab2
$Var3
$varCab3
$Vargab3

Answer 1

尝试以下（grep -oE '\$\w+' filename）：

$ cat 1.csv
Test1,$Var1,$varCab1,$Vargab1,Comment1
Test2,$Var2,$varCab2,$Vargab2,Comment2
Test3,$Var3,$varCab3,$Vargab3,Comment3
$ grep -oE '\$\w+' 1.csv
$Var1
$varCab1
$Vargab1
$Var2
$varCab2
$Vargab2
$Var3
$varCab3
$Vargab3

使用awk：

$ awk -F, '{ for(i=1;i<=NF;i++) if ($i ~ /\$/) print $i; }' 1.csv
$Var1
$varCab1
$Vargab1
$Var2
$varCab2
$Vargab2
$Var3
$varCab3
$Vargab3

Answer 2

Using perl:

perl -ne 'for (m/\$\w+/g) { print $_, "\n" }' < inputfile

Or even shorter:

perl -ne 'print map("$_\n", m/\$\w+/g)' < inputfile

Explanation:

• The regular expression \$\w+ matches a $ followed by one or more word characters.
• The m//g expression returns a list of matches.
• perl -ne runs the expression for each file in the input, inserting the line in $_, which is then used by the m//g expression.

Answer 3

使用tr和grep：

$ tr ',' '\n' < inputfile | grep "^[$]"
$Var1
$varCab1
$Vargab1
$Var2
$varCab2
$Vargab2
$Var3
$varCab3
$Vargab3