11

在下面的代码中,我收到此错误:

class Animal needs to be abstract, since: it has 5 unimplemented members. /** As seen from class Animal, the 
 missing signatures are as follows. * For convenience, these are usable as stub implementations. */ def 
 favFood_=(x$1: Double): Unit = ??? def flyingType_=(x$1: scala.designpatterns.Strategy.Flys): Unit = ??? def 
 name_=(x$1: String): Unit = ??? def sound_=(x$1: String): Unit = ??? def speed_=(x$1: Double): Unit = ???

如果我将 Animal 类的所有实例变量初始化为 _ ,那么代码就可以正确编译。这些错误是什么意思?

package scala.designpatterns

/**
 *
 * Decoupling
 * Encapsulating the concept or behaviour that varies, in this case the ability to fly
 *
 * Composition
 * Instead of inheriting an ability through inheritence the class is composed with objects with the right abilit built in
 * Composition allows to change the capabilites of objects at runtime
 */
object Strategy {

  def main(args: Array[String]) {

    var sparky = new Dog
    var tweety = new Bird

    println("Dog : " + sparky.tryToFly)
    println("Bird : " + tweety.tryToFly)
  }

  trait Flys {
    def fly: String
  }

  class ItFlys extends Flys {

    def fly: String = {
      "Flying High"
    }
  }

  class CantFly extends Flys {

    def fly: String = {
      "I can't fly"
    }
  }

  class Animal {

    var name: String
    var sound: String
    var speed: Double
    var favFood: Double
    var flyingType: Flys

    def tryToFly: String = {
      this.flyingType.fly
    }

    def setFlyingAbility(newFlyType: Flys) = {
      flyingType = newFlyType
    }

    def setSound(newSound: String) = {
      sound = newSound
    }

    def setSpeed(newSpeed: Double) = {
      speed = newSpeed
    }

  }

  class Dog extends Animal {

    def digHole = {
      println("Dug a hole!")
    }

    setSound("Bark")

    //Sets the fly trait polymorphically
    flyingType = new CantFly

  }

  class Bird extends Animal {

    setSound("Tweet")

    //Sets the fly trait polymorphically
    flyingType = new ItFlys
  }

}
4

1 回答 1

26

您必须初始化变量。如果你不这样做,Scala 假设你正在编写一个抽象类,并且一个子类将填充初始化。(如果您只有一个未初始化的变量,编译器会告诉您。)

编写= _使 Scala 填充默认值。

重点是让您思考当某人(例如您,在您忘记首先需要设置事物之后)调用使用例如未设置声音的声音时会发生什么。

(一般而言,您至少应该仔细考虑这是否是构建代码的正确方法;许多在使用前需要初始化的字段是安全的,没有任何强制初始化的机制,这是在自找麻烦。)

于 2013-08-26T21:39:37.867 回答