9

我目前正在使用以下代码将对象编组为 xml 字符串

    JAXBContext context;

    try {
        context = JAXBContext.newInstance(heartbeat.getClass());
        StringWriter writer = new StringWriter();
        Marshaller marshaller = context.createMarshaller();

        heartbeat.setHeader(header);
        heartbeat.setHeartbeatEvent(event);

        marshaller.marshal(heartbeat, writer);
        String stringXML = writer.toString();
        return stringXML;

    } catch (JAXBException e) {
        throw new RuntimeException("Problems generating XML in specified "
                + "encoding, underlying problem is " + e.getMessage(),
                e);
    }

产生以下标题

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>

我想要的输出如下

<?xml version=\"1.0\"?>

通过将此添加到编组器

marshaller.setProperty(Marshaller.JAXB_FRAGMENT, Boolean.FALSE);
marshaller.setProperty("com.sun.xml.bind.xmlHeaders", "<?xml version=\"1.0\"?>");

我收到

<?xml version="1.0" encoding="UTF-8" standalone="yes"?><?xml version="1.0"?>

并将 JAXB_FRAGMENT 属性更改为 TRUE 会完全删除标头。我一直在关注JAXB - 从生成的 XML 线程中删除 'standalone="yes"'试图解决问题,但到目前为止我还没有运气。有人可以给我一些关于如何从 JAXB 编组器获取我想要的标头的见解吗?

4

3 回答 3

24

当编组到OutputStream使用以下组合时,会产生预期的输出。

    marshaller.setProperty("com.sun.xml.bind.xmlHeaders", "<?xml version=\"1.0\"?>");
    marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);

当您编组到 a 时会出现您看到的问题Writer,这似乎是 JAXB 参考实现中的一个错误。您可以通过以下链接提出问题:


你总是可以这样做:

JAXBContext context;

try {
    context = JAXBContext.newInstance(heartbeat.getClass());
    StringWriter writer = new StringWriter();
    writer.append("<?xml version=\"1.0\"?>");
    Marshaller marshaller = context.createMarshaller();
    marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);

    heartbeat.setHeader(header);
    heartbeat.setHeartbeatEvent(event);

    marshaller.marshal(heartbeat, writer);
    String stringXML = writer.toString();
    return stringXML;

} catch (JAXBException e) {
    throw new RuntimeException("Problems generating XML in specified "
            + "encoding, underlying problem is " + e.getMessage(),
            e);
}

EclipseLink JAXB (MOXy)也支持它,com.sun.xml.bind.xmlHeaders并且在编组到 a 时它可以正常工作Writer(我是 MOXy 领导)

于 2013-08-26T19:56:36.257 回答
7

这对我有用

marshaller.setProperty("com.sun.xml.internal.bind.xmlHeaders", "<?xml version=\"1.0\" encoding=\"UTF-8\"?>");

于 2015-10-01T16:32:48.160 回答
1

在 JAXB 3.0.1 中,上述常量会导致 PropertyException:

 jakarta.xml.bind.PropertyException: name: com.sun.xml.bind.xmlDeclaration value: false

在这种情况下,可以使用以下编组器常量配置 XML 前导码:

marshaller.setProperty("org.glassfish.jaxb.xmlHeaders", "<?xml version=\"1.0\" encoding=\"UTF-8\" ?>");
marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);
于 2022-01-17T15:19:19.143 回答