3

我正在使用 codeigniter 构建自己的 REST Web 服务，该应用程序有一个名为“调用”的资源，并且可以通过POST方法访问它，

“调用”函数通过使用此内容类型的Curl调用接收四个参数[id，经理，部门，级别]作为json对象：application/json

然后我使用 codeigniter form_validation()库来验证请求，如果form_validation()上没有错误，则返回响应数组

问题是 form_validation() 总是返回 FALSE，尽管我可以按预期输出接收到的值。

下面是调用函数的代码

function calls_post() {

$this->load->model('api/central');
$this->load->library('form_validation');

//validation rules
$this->form_validation->set_error_delimiters('', '');
$this->form_validation->set_rules('id', 'id', 'required|numeric');
$this->form_validation->set_rules('manager', 'manager', 'required|numeric');
$this->form_validation->set_rules('department', 'department', 'required');
$this->form_validation->set_rules('level', 'level', 'required|numeric');


if ($this->form_validation->run() === FALSE) {

    $employeeId = $this->form_validation->error('id') ? $this->form_validation->error('id') : $this->post('id');
    $manager = $this->form_validation->error('manager') ? $this->form_validation->error('manager') : $this->post('manager');
    $department = $this->form_validation->error('department') ? $this->form_validation->error('department') : $this->post('department');
    $level = $this->form_validation->error('level') ? $this->form_validation->error('level') : $this->post('level');

    $response = array(
        'status' => FALSE,
        'error' => 'We don\'t have data to display, Minimum information required to process the request is missing',                
        'authenticated' => true,                
        'id' => $employeeId,
        'manager' => $manager,
        'department' => $department,
        'level' => $level                
    );

    $this->response($response, 200);

} else {

    $response = $this->central->calls_get($this->post('id'), $this->post('manager'), $this->post('department'), $this->post('level'));
    $this->response($response);
}
}

有什么建议吗？:)

4

1 回答 1

13

http://ellislab.com/forums/viewthread/238080

$_POST = json_decode(file_get_contents("php://input"), true);
$this->form_validation->set_rules('id', 'id', 'required|numeric');
$this->form_validation->set_rules('department', 'department', 'required');

if($this->form_validation->run() == TRUE)
{   
    $id = $this->input->post('id'); 
    $department = html_escape($this->input->post('department'));    
    echo $id."<br>".$department;       
}
else
{   
    echo "false";        
}
于 2014-06-25T06:36:24.247 回答