1


我有一个 XMLType 对象，我想将开放时间提取到表中。

<workspace>
  <title>workspace1</title>
  <item>
    <day>1</day>
    <openingTime>8:00</openingTime>
    <closingTime>12:00</closingTime>
  </item>
  <item>
    <day>1</day>
    <openingTime>13:00</openingTime>
    <closingTime>18:00</closingTime>
  </item>
<workspace>
<workspace>
  <title>workspace2</title>
  <item>
    <day>1</day>
    <openingTime>9:00</openingTime>
    <closingTime>14:00</closingTime>
  </item>
  <item>
    <day>3</day>
    <openingTime>12:00</openingTime>
    <closingTime>16:00</closingTime>
  </item>
<workspace>

我会使用类似的东西：

SELECT ExtractValue(Value(p),'workspace/item/day/text()') as day
      ,ExtractValue(Value(p),'workspace/item/openingTime/text()') as open
      ,ExtractValue(Value(p),'workspace/item/closingTime/text()') as close
      FROM TABLE (XMLSequence(Extract(y,'workspace'))) p
      WHERE ExtractValue(Value(p),'/workspace/title/text()') LIKE 'workspace1';

其中y是上面的 XMLType。但这不起作用，因为它仍然会找到多个项目节点。我需要提取标题 workspace2 的所有元素值（值 1、9:00、14:00、3、12:00、16:00）。如果我不仅可以提取值，而且可以提取 XMLType 的整个部分，那将会有所帮助。有任何想法吗？
谢谢， 迈克尔

4

2 回答 2

2

您的目标可以通过使用XMLTable来实现：

with x as ( -- Just to introduce XML parameter
  select 
    xmltype('
       <workspace_list>     
        <workspace>
          <title>workspace1</title>
          <item>
            <day>1</day>
            <openingTime>8:00</openingTime>
            <closingTime>12:00</closingTime>
          </item>
          <item>
            <day>1</day>
            <openingTime>13:00</openingTime>
            <closingTime>18:00</closingTime>
          </item>
        </workspace>
        <workspace>
          <title>workspace2</title>
          <item>
            <day>1</day>
            <openingTime>9:00</openingTime>
            <closingTime>14:00</closingTime>
          </item>
          <item>
            <day>3</day>
            <openingTime>12:00</openingTime>
            <closingTime>16:00</closingTime>
          </item>
        </workspace>
       </workspace_list>     
  ') xfield
  from dual
)  
select 
  workspace, day, opening_time, closing_time
from
 XMLTable(
   '
     for $i in $doc//workspace[title eq $workspace_filter]
     for $j in $i/item 
     return 
      <wks_item>
        <wks_name>{$i/title/text()}</wks_name> 
        {$j/*}
      </wks_item> 
   '
   passing 
    (select xfield from x) as "doc",
    ('workspace1')         as "workspace_filter"
   columns
   workspace     varchar2(100) path '//wks_name',
   day           varchar2(100) path '//day',
   opening_time  varchar2(100) path '//openingTime',
   closing_time  varchar2(100) path '//closingTime'
 )

SQLFiddle Example

请注意，我引入了<workspace_list>顶部元素并为关闭<workspace>元素添加了斜线以使 XML 有效。

于 2013-08-26T14:58:53.813 回答
1

使用一些@ThinkJet 技巧，您的查询可能看起来像这样

with x as (
  select 
    xmltype('
       <workplaces>     
        <workspace>
          <title>workspace1</title>
          <item>
            <day>1</day>
            <openingTime>8:00</openingTime>
            <closingTime>12:00</closingTime>
          </item>
          <item>
            <day>1</day>
            <openingTime>13:00</openingTime>
            <closingTime>18:00</closingTime>
          </item>
        </workspace>
        <workspace>
          <title>workspace2</title>
          <item>
            <day>1</day>
            <openingTime>9:00</openingTime>
            <closingTime>14:00</closingTime>
          </item>
          <item>
            <day>3</day>
            <openingTime>12:00</openingTime>
            <closingTime>16:00</closingTime>
          </item>
        </workspace>
       </workplaces>     
  ') xfield
  from dual
)
SELECT "day", "openingTime", "closingTime"
FROM xmltable('$doc//workspace[title=$workspace_filter]/item'
              passing (select xfield from x) as "doc",
                      ('workspace1') as "workspace_filter"
               columns "openingTime" path '//openingTime',
                       "closingTime" path '//closingTime',
                       "day" path '//day')
于 2013-08-26T15:21:03.120 回答