如果单击按钮(获取值),我需要数据库中的所有值,我该怎么办?请帮助我任何人有什么办法做到这一点?
this is my index.php
<script type="text/javascript" src="jquery-1.10.1.js"></script>
<form>
<h1>Insert Data Into mySQL Database</h1>
Name <input name="name" type="text" id="name"> <br><br>
Lastname <input name="lastname" type="text" id="lastname"><br><br>
Email <input name="email" type="text" id="email"><br><br>
<input type="button" name="Submit" value="Submit" onclick="insertData()">
</form>
<button type="button">get values</button>
<div id="jcontent"></div>
<script type="text/javascript">
/* * Checking the Login - * */
function insertData(){
var data_get = {
'name_form': $('#name').val().trim(),
'lastname_form': $('#lastname').val().trim(),
'email_form': $('#email').val().trim()
};
$.ajax({
url : 'insert_ac.php',
type : 'POST',
data : data_get,
timeout : 30000,
success : function(response_data, text, xhrobject) {
console.log(text);
if(text == "success"){
$('#jcontent').html('Data Inserted');
}
else if(text == "ERROR"){
$('#jcontent').html('data not inserted');
}
}
});
}
</script>
/*******************************************************/
this is my insert.php
<?php
mysql_connect('localhost','root','');
mysql_select_db('loginthree');
$table_name = "test_three";
$name_form=$_POST['name_form'];
$lastname_form=$_POST['lastname_form'];
$email_form=$_POST['email_form'];
$sql="INSERT INTO $table_name(name, lastname, email)VALUES('$name_form', '$lastname_form', '$email_form')";
$result=mysql_query($sql);
// if successfully insert data into database, displays message "Successful".
if($result){
echo "Success";
} else {
echo "ERROR";
}
?>
<?php
// close connection
mysql_close();
?>
如果单击按钮(获取值),我需要数据库中的所有值,我该怎么办?请帮助我任何人有什么办法做到这一点?