14

目前我正在使用 ASP.NET MVC 4 和Code First Approach研究 C# 。我是 Visual Basic 开发人员，现在我想开始 C#。而且，现在我遇到了我必须管理多重继承的情况。但是，我认为 Class 是不可能的。那么，我应该如何管理我拥有的这些课程：

//I have the Following Person Class which Hold Common Properties 
//and a Type of Person e.g : Student, Faculty, Administrative
public class Person
{
    public int Id { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public string Type { get; set; }
}


//This is my Student Class, which is Derived from Person
public class Student : Person
{
    public DateTime DateOfBirth { get; set; }
    public DateTime EnrollmentDate { get; set; }
    public string Remarks { get; set; }

    public bool Approved { get; set; }
    public DateTime ApprovedDate { get; set; }
    public int ApprovedUserId { get; set; }
}


//This is my Faculty Class, which is also Derived from Person
public class Faculty : Person
{
    public DateTime HiredDate { get; set; }

    public bool Approved { get; set; }
    public DateTime ApprovedDate { get; set; }
    public int ApprovedUserId { get; set; }
}

我想做的是 Approved、ApprovedDate 和 ApprovedUserId 也很常见。我想指定这些属性，例如：

 public class Approve {
    public bool Approved { get; set; }
    public DateTime ApprovedDate { get; set; }
    public int ApprovedUserId { get; set; }
}

并且，想像这样使用：

public class Student : Person, Approve
{
    public DateTime DateOfBirth { get; set; }
    public DateTime EnrollmentDate { get; set; }
    public string Remarks { get; set; }
}

而且，我不能把这些东西放在PERSON里面。因为，我必须将它用于另一个类，但那些不是Person。

那么，我该如何实现这一目标......

请给我一个上述情况的例子。

请帮忙。而且，非常感谢您提前。

4

6 回答 6

25

一种可能的解决方案是修改您的层次结构：

public class PersonWithApprove : Person { // TODO: replace with non disgusting name
    public bool Approved { get; set; }
    // etc...
}

public class Student : PersonWithApprove {
}

public class Faculty : PersonWithApprove {
}

或者你可以创建一个接口：

public interface IApprove {
    bool Approved { get; set; }
    // etc
}

public class Student : Person, IApprove {
}

您也可以这样离开该类Approve，并拥有具有该类型属性的类：

public class Student : Person {
    Approve _approve = new Approve();
    public Approve Approve {
        get { return _approve; }
    }
}
于 2013-08-26T07:02:32.827 回答
6

恕我直言，在这里使用接口是一个很好的例子，如下所示：

  // Interfaces:

  // General person
  public interface IPerson {
    int Id { get; set; }
    string FirstName { get; set; }
    string LastName { get; set; }
    string Type { get; set; }
  }

  // Approvable person
  public interface IApprovable {
    bool Approved { get; set; }
    DateTime ApprovedDate { get; set; }
    int ApprovedUserId { get; set; }
  } 

  // Student is a IPerson + IApprovable
  public interface IStudent: IPerson, IApprovable {
    DateTime DateOfBirth { get; set; }
    DateTime EnrollmentDate { get; set; }
  }

  // So classes will be

  public class Approve: IApprovable {
    ... //TODO: Implement IApprovable interface here
  } 

  public class Faculty: IPerson, IApprovable {
    public DateTime HiredDate { get; set; }

    ... //TODO: Implement IPerson interface here
    ... //TODO: Implement IApprovable interface here
  }

  public class Student: IStudent {
    public string Remarks { get; set; }

    ... //TODO: Implement IStudent interface here
  }
于 2013-08-26T07:14:37.517 回答
5

简答

考虑改用接口，它允许多重继承并且可以使用interface关键字声明。

长答案

从 C# 中的多个基类继承是非法的。类可能只有 1 个基类，而它们可以实现任意数量的接口。这有几个原因，但主要归结为多重继承在类层次结构中引入了更多的复杂性。

接口用于声明一组必须由类实现的通用功能（方法和属性）。

要修改现有代码以使用接口（而不是多重继承），您可以执行以下操作：

public interface IApprove // Defines a set of functionality that a class must implement.
{
    // All these properties must be inherited as public when implemented.
    bool Approved { get; set; } // Property declaration.
    DateTime ApprovedDate { get; set; }
    int ApprovedUserId { get; set; }
}

public class Student : Person, IApprove
{
    public DateTime DateOfBirth { get; set; }
    public DateTime EnrollmentDate { get; set; }
    public string Remarks { get; set; }

    #region IApprove Implementation

    private bool _approved; // Private variable that is accessed through the 'Approved' property of the 'IApprove' interface.
    public bool Approved // Defines 'Approved' inherited from IApprove
    {
        get { return _approved; }
        set { _approved = value; }
    }

    private DateTime _approvedDate;
    public DateTime ApprovedDate // Defines 'ApprovedDate' inherited from IApprove.
    {
        get { return _approvedDate; }
        set { _approvedDate = value; }
    }

    private int _approvedUserId;
    public int IApprove.ApprovedUserId // Alternative syntax to define an interfaces property.
    {
        get { return _approvedUserId; }
        set { _approvedUserId = value; }
    }

    #endregion
}

这种方法抽象了IApprove接口的实现，并且像多重继承一样，允许用户对实现IApprove的对象进行操作，但它们的具体类型是未知的（或不相关的）。

有关 C# 中接口使用的更多信息，请参阅：

http://msdn.microsoft.com/en-us/library/87d83y5b.aspx

于 2013-08-26T07:41:57.107 回答
3

考虑以下示例，它使用两个接口：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;


////////
////////
/// Multiple Inheritance With Interfaces

public interface Interface1
{
    void func1();
    void fun();
}

public interface Interface2
{
    void func2();
    void fun();
}

public class MyTestBaseClass : Interface1, Interface2
{
    void Interface1.func1()
    {
        Console.WriteLine("From MyInterface1 Function()");
        return;
    }


    void Interface2.func2()
    {
        Console.WriteLine("From MyInterface2 Function()");
        return;
    }

    void Interface1.fun()
    {
        Console.WriteLine("fun1()");
    }

    void Interface2.fun()
    {
        Console.WriteLine("fun2()");
    }


    public static void Main()
    {
        MyTestBaseClass myclass = new MyTestBaseClass();
        ((Interface1)myclass).func1();
        ((Interface2)myclass).func2();
    }

}
于 2014-02-18T22:52:10.460 回答
2

您可以使用复合模式

    public class Student:Person
    {
        public Approve App { get; set; }
        public DateTime DateOfBirth { get; set; }
        public DateTime EnrollmentDate { get; set; }
        public string Remarks { get; set; }
    }
于 2013-08-26T07:00:02.150 回答
1

使用装饰器设计模式的一些基本示例：

public class Class1
{
    public void Method1()
    {
        Console.write($"Class1: Method1, MyInt: {MyInt}");
    }

    public int MyInt { get; set; }
}

public class Class2
{
    public void Method2()
    {   
        Console.write($"Class2: Method2, MyInt: {MyInt}");      
    }

    public int MyInt { get; set; }
 }

public class MultipleClass
{
    private Class1 class1 = new Class1();
    private Class2 class2 = new Class2();

    public void Method1()
    {
        class1.Method1();
    }
    public void Method2()
    {
        class2.Method2();
    }

    private int _myInt;
    public int MyInt
    {
        get { return this._myInt; }
        set
        {
            this._myInt = value;
            class1.MyInt = value;
            class2.MyInt = value;
        }
    }
}

演示：

 MultipleClass multipleClass = new MultipleClass();
 multipleClass.Method1(); //OUTPUT: Class1: Method1, MyInt: 1 
 multipleClass.Method2(); //OUTPUT: Class2: Method2, MyInt: 1
 multipleClass.MyInt = 1;
于 2017-11-08T12:38:44.127 回答