更新的解决方案:
我从接受的答案中稍微改变了一些(这使我走上了正确的轨道,所以我没有提交新的答案):
<table class="fixed">
<tr>
<th>Student Name</th>
<!-- create as many <th> as there are evaluations -->
<% @eval_count.times do |i| %>
<th>Evaluation <%= i+1 %></th>
<% end %>
<th>Student Average <br />(for this goal)</th>
</tr>
<% for eval in @evals %>
<tr class="<%= cycle("odd", "even", name: "evals")%>">
<!-- eval returns { s_id [eval],[eval]} -->
<td><%= eval[1].first.student.name%></td>
<!-- in each student's row, print the score for each consecutive evaluation -->
<% @eval_count.times do |i| %>
<td><%= eval[1][i].score %></td>
<% end %>
</tr>
<% reset_cycle("evals") %>
<% end %>
</table>
结束更新
目前我认为以下内容(我知道这很丑陋,我只是这样做,所以在我测试时一切都在同一页面上,当它工作时我会清理它!):
<div class="holder2 round">
<% if @goal.avg.nan? %>
<p>
This goal has not been evaluated yet!
</p>
<% else %>
<%= render 'evaluations_by_goal' %>
<% end %>
</div>
_evaluations_by_goal.html.erb
:
<% ordered_evals_by_goal = @goal.evaluations.order("eval_number").all.group_by { |g| g.eval_number } %>
<h3>
The overall average for this goal is <%= @goal.avg %>
</h3>
<table>
<tr>
<th>Student Name</th>
<th>Evaluation 1</th>
<th>Evaluation 2</th>
</tr>
<% @scores = [] %>
<% ordered_evals_by_goal.each do |number, evals| %>
<% evals.in_groups(evals.count, false) do |group| %>
<% group.each do |eval| %>
<tr>
<td><%= eval.student.name %></td>
<td><%= eval.score %></td>
<td>**others here**</td>
</tr>
<% end %>
<% end %>
<% end %>
</table>
编辑:
所以你可以看到哈希的结构,ordered_evals_by_goal
输出这个:
{22=>
[#<Evaluation id: 1702, score: 4, created_at: "2013-08-25 11:00:58", updated_at: "2013-08-25 11:00:58", student_id: 22, goal_id: 28, eval_number: 22>,
#<Evaluation id: 1710, score: 3, created_at: "2013-08-25 11:01:08", updated_at: "2013-08-25 11:01:08", student_id: 23, goal_id: 28, eval_number: 22>,
#<Evaluation id: 1718, score: 3, created_at: "2013-08-25 11:01:15", updated_at: "2013-08-25 11:01:15", student_id: 24, goal_id: 28, eval_number: 22>,
#<Evaluation id: 1726, score: 3, created_at: "2013-08-25 11:01:21", updated_at: "2013-08-25 11:01:21", student_id: 25, goal_id: 28, eval_number: 22>],
23=>
[#<Evaluation id: 1734, score: 3, created_at: "2013-08-25 11:02:18", updated_at: "2013-08-25 11:02:18", student_id: 22, goal_id: 28, eval_number: 23>,
#<Evaluation id: 1742, score: 3, created_at: "2013-08-25 11:02:27", updated_at: "2013-08-25 11:02:27", student_id: 23, goal_id: 28, eval_number: 23>,
#<Evaluation id: 1750, score: 3, created_at: "2013-08-25 11:02:35", updated_at: "2013-08-25 11:02:35", student_id: 24, goal_id: 28, eval_number: 23>,
#<Evaluation id: 1758, score: 3, created_at: "2013-08-25 11:02:42", updated_at: "2013-08-25 11:02:42", student_id: 25, goal_id: 28, eval_number: 23>]}
结束编辑
目前,它输出以下内容:
但是在学生姓名开始循环的地方,我希望分数数据进入空的 td 以便整个表(在这种情况下)总共有 5 行 - 一个表头和四个表数据。我怎样才能做到这一点?