1

我正在检查事物的尺寸，我想知道从最大到最小的 3 个尺寸。

所以这是我写的有点“神乎其神”的函数：

CREATE FUNCTION dbo.SortDimensions
    ( @aDim1 udt_Dimension
    , @aDim2 udt_Dimension
    , @aDim3 udt_Dimension 
    )
RETURNS @rDimensions TABLE 
    ( Dim1 udt_Dimension
    , Dim2 udt_Dimension
    , Dim3 udt_Dimension 
    )
AS
BEGIN
  ; WITH OrderedDims ( Dimension ) AS ( 
                SELECT @aDim1
      UNION ALL SELECT @aDim2
      UNION ALL SELECT @aDim3
   )
  ,      Pairs ( Name, Value ) AS ( 
      SELECT 'Dim' + CAST( ROW_NUMBER() OVER (ORDER BY( Dimension ) DESC ) AS varchar ), Dimension 
        FROM OrderedDims 
  )
  INSERT INTO @rDimensions ( Dim1, Dim2, Dim3 )
      SELECT MAX(Dim1), MAX(Dim2), MAX(Dim3) 
        FROM Pairs 
      PIVOT ( MAX(Value) FOR Name IN ( [Dim1], [Dim2], [Dim3] )) p

  RETURN
END

做与此相同的事情不是很多工作：

DECLARE @lDim1 udt_Dimension
DECLARE @lDim2 udt_Dimension 
DECLARE @lDim2 udt_Dimension

IF @aDim2 > @aDim1 
  BEGIN
    SELECT @lDim1 = @aDim2 
         , @lDim2 = @aDim1
  END
ELSE 
  BEGIN 
    SELECT @lDim1 = @aDim1 
         , @lDim2 = @aDim2
  END

IF NOT @aDim3 > @aDim2 
  BEGIN 
    SET @lDim3 = @aDim3
  END
ELSE
  BEGIN
    SET @lDim3 = @lDim2
    IF @aDim3 > @lDim1 
      BEGIN
        SET @lDim2 = @lDim1
        SET @lDim1 = @aDim3
      END
    ELSE 
      BEGIN
        SET @lDim2 = @aDim3
      END
  END 

INSERT INTO @rDimensions VALUES ( @lDim1, @lDim2, @lDim3 )

我相信一位 DBA 曾经告诉我，设计 SQL 服务器的人将临时表技术重用于变量，因此它几乎是表和变量之间的清洗。（如果这不是真的，请继续打消我这个想法。）

4

1 回答 1

1

我很确定这应该更快：

CREATE FUNCTION dbo.SortDimensions
    ( @aDim1 udt_Dimension
    , @aDim2 udt_Dimension
    , @aDim3 udt_Dimension 
    ) RETURNS TABLE
AS RETURN
(
    WITH cte As (     SELECT @aDim1 As Dim
            UNION All SELECT @aDim2
            UNION ALL SELECT @aDim3
    )
    , cte2 As ( SELECT Dim, ROW_NUMBER() OVER(ORDER BY Dim) As Odr FROM cte )
    SELECT  
            MAX(CASE WHEN Odr=1 THEN Dim ELSE NULL END) As Dim1,
            MAX(CASE WHEN Odr=2 THEN Dim ELSE NULL END) As Dim2,
            MAX(CASE WHEN Odr=3 THEN Dim ELSE NULL END) As Dim3
    FROM    cte2
)
于 2013-08-25T02:13:37.483 回答