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请原谅这可能是一个非常基本的问题，但我正在编写一个程序来存储员工信息，它工作正常，直到它尝试在我的员工类中设置信息。它给出了一个stackoverflow错误，我不知道为什么。谢谢你的帮助。

主类：

import java.util.Scanner;

public class Main
{
    public static void main(String[] args)
    {
        Scanner Input = new Scanner(System.in);

        System.out.println("Enter the number of employees to enter.");
        int employeeCount = Input.nextInt();
        Input.nextLine();

        Employee employee[] = new Employee[employeeCount];
        String namesTemp;
        String streetTemp;
        String cityTemp;
        String stateTemp;
        String zipCodeTemp;
        String address;
        String dateOfHireTemp;

        for(int x = 0; x < employeeCount; x++)
        {
            System.out.println("Please enter the name of Employee " + (x + 1));
            namesTemp = Input.nextLine();
            System.out.println("Please enter the street for Employee " + (x + 1));
            streetTemp = Input.nextLine();
            System.out.println("Please enter the city of Employee " + (x + 1));
            cityTemp = Input.nextLine();
            System.out.println("Please enter the state of Employee " + (x + 1));
            stateTemp = Input.nextLine();
            System.out.println("Please enter the zip code of Employee " + (x + 1));
            zipCodeTemp = Input.nextLine();
            address = streetTemp + ", " + cityTemp + ", " + stateTemp + ", " + zipCodeTemp;
            System.out.println("Please enter the date of hire for Employee " + (x + 1));
            dateOfHireTemp = Input.nextLine();
            System.out.println("The employee ID for employee " + (x + 1) + " is " + (x + 1));
            employee[x] = new Employee(x, namesTemp, address, dateOfHireTemp);
        }
    }
}

员工等级：

public class Employee
{
    private int employeeID;
    private Name name;
    private Address address;
    private DateOfHire hireDate;

    public Employee()
    {

    }

    public Employee(int employeeID, String name, String address, String hireDate)
    {
        String temp;
        Name employeeName = new Name(name);
        this.employeeID = employeeID;
    }
}

名称类：

public class Name 
{
    public Name name;

    public Name(String name)
    {
        Name employeeName = new Name(name);
        this.name = employeeName;
    }
}
4

2 回答 2

8

StackoverflowExceptions 最常见的原因是在不知不觉中进行了递归，这是否发生在这里？...

public Name(String name)
{
    Name employeeName = new Name(name);  // **** YIKES!! ***
    this.name = employeeName;
}

宾果游戏：递归！

此构造函数将创建一个新的 Name 对象，其构造函数将创建一个新的 Name 对象，其构造函数将......因此您将无限期地创建新的 Name 对象或直到堆栈内存耗尽。解决方案：不要这样做。将名称分配给字符串：

class Name {
    String name; // ***** String field!

    public Name(String name)
    {
        this.name = name;  // this.name is a String field
    }
于 2013-08-24T18:42:54.177 回答
2

通常，一个类用于将数据与功能组合在一起。看起来Name该类只是 a 的包装器，String没有添加任何功能。在您的 Java 职业生涯中，最好String name;在Employee类中声明并一起删除Name该类。（请注意，这将从您的代码中删除 Hovercraft Full of Eels 描述的错误。）

于 2013-08-24T18:55:24.740 回答